CODEWITHSUNDEEP
c#.netstringlinqsplit
Glory Raj
Glory Raj

Reputation: 17691

Splitting string into multiple strings using LINQ

I am trying to split this string

string s = "sn DC0000002; mac 00:0c; uuid 564d6ae4-979";

I need to get these values from above string "DC0000002" , "00:0c" , "564d6ae4-979"

For this I have tried below query but not able to able to get last two values I mean these two values ("00:0c" , "564d6ae4-979")

Below is the query for splitting 

List<string> decryptedList = new List<string>();
decryptedList = decodePP.Split(';').Select(x => x.Split(' ')[1]).ToList();

orgSNo = decryptedList[0]; //Output - DC0000002
orgMacID = decryptedList[1];// output - mac // this is wrong need to get value
orgUUID = decryptedList[2]; //output - uuid // this is also wrong

Would anyone please help on this query how extract values from the above string using LINQ query in a single shot?

Upvotes: 0

Views: 2117

Answers (3)

miezke
miezke

Reputation: 51

You could use the TrimStart() function in your linq statement like:

decryptedList = decodePP.Split(';').Select(x => x.TrimStart().Split(' ')[1]).ToList();

Upvotes: 0

amcdermott
amcdermott

Reputation: 1585

Why do you need to use Linq. The string split would seem to do the trick?

string[] keyValuePairs = s.Split(';');

foreach(string pair.Trim() in keyValuePairs)
{
   string key = pair.Split(' ')[0].Trim();
   string value = pair.Split(' ')[1].Trim();
}

That's only a stab at the code - it may not compile, but you get the idea?

Upvotes: 0

Sergey Berezovskiy
Sergey Berezovskiy

Reputation: 236208

Just trim substrings which you get after first split:

decodePP.Split(';').Select(x => x.Trim().Split(' ')[1]).ToList();

You get incorrect results, because first split gives you

[ "sn DC0000002", " mac 00:0c", " uuid 564d6ae4-979" ]

As you can see, items except first one have leading whitespace.

Alternative solution - you can use StringSplitOptions.RemoveEmptyEntries parameter to skip empty substrings

str.Split(';')
   .Select(x => x.Split(new char[]{' '}, StringSplitOptions.RemoveEmptyEntries)[1])
   .ToList()

Upvotes: 5

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