Mitch
Mitch

Reputation: 177

How to continue after an exception? Python

I have a for loop that's parsing data being pulled from Yelp. Sometimes, I get the following exception due to some of the business names:'ascii' codec can't encode character u'\xf1' in position 3: ordinal not in range(128). Since this is pretty common, I would like my for loop to continue iterating after this exception skipping the line that's throwing the exception. What would be the best way? For some reason using continue doesn't work for me.

try:
    response = json.loads(conn.read())
    yelp_data =[x for x in response['businesses']]
    logger.info('Connection to yelp was made')
    data_len = len(yelp_data)
    while data_len > 0:
        for line in yelp_data:
            address = [x.encode('UTF8') for x in line['location']['display_address']]
            cat =[','.join([str(c) for c in lst]) for lst in line['categories']]
            Category =','.join(cat)
            target.submit( 'Name = {},Rating = {},URL = {},Review_Count = {},Phone = {},Yelp_ID = {},Address = {}, Category = {}\n'.format(line.get('name'),line.get('rating'),line.get('mobile_url'),line.get('review_count'),line.get('phone'),line.get('id'),", ".join(address), Category),sourcetype=sourcetype)
            data_len = data_len -1

except Exception as e:
    logger.error(e)

Upvotes: 1

Views: 149

Answers (1)

Rahul Tripathi
Rahul Tripathi

Reputation: 172618

You can try to move the try/except inside the while loop

while data_len > 0:
    try:
        for line in yelp_data:
            address = [x.encode('UTF8') for x in line['location']['display_address']]
            cat =[','.join([str(c) for c in lst]) for lst in line['categories']]
            Category =','.join(cat)
            target.submit( 'Name = {},Rating = {},URL = {},Review_Count = {},Phone = {},Yelp_ID = {},Address = {}, Category = {}\n'.format(line.get('name'),line.get('rating'),line.get('mobile_url'),line.get('review_count'),line.get('phone'),line.get('id'),", ".join(address), Category),sourcetype=sourcetype)
            data_len = data_len -1

    except Exception as e:
        logger.error(e)

Upvotes: 3

Related Questions