CODEWITHSUNDEEP
javascriptregexparsingextendscriptafter-effects
Amaylayinsues
Amaylayinsues

Reputation: 51

Javascript parsing?

I'm coding something in extendscript for adobe after effects, which ends up being javascript.

I have an array and I would like to do a search for just the word "assemble" and return the whole jc3_RIG_008_masterLayer assemble string

var comps = ["_MAIN", "jc3_RIG_008_masterLayer assemble","jc3_RIG_008_masterLayer contact sheet", "[Z] source", "MM004 source"];

I'm not sure what the best/ most efficient way to achieve this is, but any thoughts would help.

Thanks.

Upvotes: 2

Views: 157

Answers (3)

Mackan
Mackan

Reputation: 6271

A normal for-loop should do the trick. This is the fastest way according to some sources. Also using indexOf() is faster than using search() according to other sources:

for (var i = 0, len = comps.length; i < len ; i++) {
   if (comps[i].indexOf('assemble') > -1) return comps[i]; //or store and break
}


var comps = ["_MAIN", "jc3_RIG_008_masterLayer assemble","jc3_RIG_008_masterLayer contact sheet", "[Z] source", "MM004 source"];

    comps.forEach(function(el) {
       if (el.indexOf('assemble') > -1) document.write('loop 1: ' + el + '<br>');
    });


    for (var i = 0, len = comps.length; i < len ; i++) {
       if (comps[i].indexOf('assemble') > -1) document.write('loop 2: ' + comps[i]);
    }
<div id="output"></div>

I'll keep this here as reference:

Something like this would work for anything with ECMAScript5 support (but according to sources, and @frxstrem, this is not available in ExtendedScript):

comps.forEach(function(el) {
   if (el.indexOf('assemble') > -1) return el;
});

Upvotes: 1

Mike
Mike

Reputation: 251

@josegomezr has the right idea using a simple loop. I updated that idea to return the string that the poster is looking for.

var comps = ["_MAIN", "jc3_RIG_008_masterLayer assemble","jc3_RIG_008_masterLayer contact sheet", "[Z] source", "MM004 source"];
var compWithAssemble;
for(var i in comps){
    if(comps[i].indexOf("assemble") > -1){
        compWithAssemble = comps[i];
        break;
    }
}
// compWithAssemble has the string you are looking for.
console.log(compWithAssemble);

Upvotes: 2

josegomezr
josegomezr

Reputation: 916

If it is plain JS you can do this:

var found = false;
for(var i in comps){
    if(comps[i].search("assemble") != -1){
        found = true;
        break;
    }
}
if(found){
    // your code if found
}else{
    // your code if not.
}

Upvotes: 0

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