Reputation: 681
I'm creating a workflow to build custom e-mail templates. In my folder, I have this structure:
folder/
templates/
template-001.html
image-001.jpg
images/
image-default.jpg
src/
style.scss
I'm using gulp-inline-css
to get the compile css file and insert all the styles inline in the file template-001.html
. Then, the task gets all these files and put inside a build
folder. Like this:
folder/
templates/
template-001.html
image-001.jpg
images/
image-default.jpg
src/
style.scss
build/
template-001.html
image-default.jpg
image-001.jpg
This is ok for an individual project. But I want to be able to build several templates and organize the files the proper way. I would like to have a folder structure like this:
folder/
templates/
template-001/
template-001.html
image-001.jpg
images/
image-default.jpg
src/
style.scss
build/
template-001/
template-001.html
image-default.jpg
image-001.jpg
In other words, I want to be able to get the folder of the template-001.html
and reproduce it in the build
folder. With my current setup, I don't know how to make it possible.
Here's my gulpfile.js
:
var gulp = require( 'gulp' ),
sass = require( 'gulp-sass' ),
autoprefixer = require( 'gulp-autoprefixer' ),
minifycss = require( 'gulp-minify-css' ),
imagemin = require( 'gulp-imagemin' ),
rename = require( 'gulp-rename' ),
concat = require( 'gulp-concat' ),
plumber = require( 'gulp-plumber' ),
notify = require( 'gulp-notify' ),
inlineCss = require('gulp-inline-css'),
projectTitle = 'E-mail Templates';
// styles task
gulp.task( 'styles', function() {
return gulp.src( 'src/*.scss' )
.pipe( plumber() )
.pipe( sass({ paths: ['src/'] }) )
.pipe( notify( {
title: projectTitle,
message: 'File: <%= file.relative %> was compiled!'
} ) )
.pipe( autoprefixer( 'last 2 version', 'safari 5', 'ie 8', 'ie 9', 'opera 12.1', 'ios 6', 'android 4' ) )
.pipe( gulp.dest( 'src/' ) )
.pipe( notify( {
title: projectTitle,
message: 'Minified file: <%= file.relative %> was created / updated!'
} ) )
console.log( '<%= file %>' );
} );
// styles task
gulp.task( 'html-build', function() {
return gulp.src( 'templates/**/*.html' )
.pipe( inlineCss({
applyStyleTags: false,
applyLinkTags: true,
removeStyleTags: false,
removeLinkTags: true
}) )
.pipe( gulp.dest('build/') )
.pipe( notify( {
title: projectTitle,
message: 'Template File: <%= file.relative %> was created / updated!'
} ) )
} );
// images task
gulp.task( 'images', function() {
return gulp.src( 'images/**/*' )
.pipe( plumber() )
.pipe( imagemin({ optimizationLevel: 7, progressive: true, interlaced: true }) )
.pipe( gulp.dest( 'build/' ) )
.pipe( notify( {
title: projectTitle,
message: 'Image: <%= file.relative %> was optimized!'
} ) )
} );
// watch task
gulp.task( 'watch', [ 'styles' ], function() {
// Watch .scss files
gulp.watch( 'src/**/*.scss', [ 'styles', 'html-build' ] );
// Watch .html files
gulp.watch( 'templates/**/*.html', [ 'html-build' ] );
// Watch image files
gulp.watch('images/**/*', ['images'] );
});
Any tips or advices about hot to make it possible? Thanks!
Upvotes: 2
Views: 6573
Reputation: 7574
So, you want to copy all files from the template folder which aren't HTML to the dest folder?
gulp.task('copy', function() {
return gulp.src(['templates/**/*','!templates/**/*.html'])
.pipe(gulp.dest('build'));
});
This will take this:
folder/
templates/
template-001/
template-001.html
image-001.jpg
template-002/
template-002.html
image-002.jpg
template-003/
template-003.html
image-003.jpg
and create this:
folder/
build/
template-001/
image-001.jpg
template-002/
image-002.jpg
template-003/
image-003.jpg
This should do the trick and work with your other tasks. When I interpreted your Gulpfile correctly, the HTML files should already be in place. Do you also need help in copying the files in images
?
I reworked the images
task. Please read the comments to know what's going on:
var fs = require('fs');
gulp.task('images', function(done) {
// get all the directories inside templates. this will return
// an array of folders
var templates = fs.readdirSync('templates').filter(function(el) {
return fs.statSync('templates/' + el).isDirectory()
});
// we start our stream with all the files from images we want to have
var stream = gulp.src( 'images/**/*' )
.pipe(plumber())
.pipe(imagemin({ optimizationLevel: 7, progressive: true, interlaced: true }));
// now we add a destination dir for each one of our
// templates
templates.forEach(function(el) {
stream.pipe(gulp.dest('templates/' + el));
});
// we add the rest of our pipes
stream.pipe(notify({
title: projectTitle,
message: 'Image: <%= file.relative %> was optimized!'
}));
// returning the stream kicks it off
return stream;
});
Upvotes: 1