Reputation: 189
I'm here with following problem. I have table with multiple records. Each row represents news of some kind, so I need to distinguish one from the another. The way to do that, is to make a table for each of these news(or a wrapper of some kind), however I encoutred a problem with fetching each result to each table(wrapper).
I can't figure out how to tell SQL to put the record separatley. Below is chunk of my code, as well as the design for the table.
.news{
width:400px;
height:auto;
border: 1px solid red;
float:left;
}
.news tr:first-child{
font-weight: bold;
height:40px;
text-align: center;
}
.news tr:last-child{
background-color: whitesmoke;
height: 200px;
padding-bottom: auto;
text-align: center;
}
.details td{
width:200px;
height: 40px;
text-align: center;
}
echo "<table class='news'>";
while ($row = mysqli_fetch_array($result)) {
echo "<tr>
<td colspan='2'>
$row[0]
</td>
</tr>
<tr class='details'>
<td>
$row[1]
</td>
<td>
$row[2]
</td>
</tr>
<tr>
<td colspan='2'>
$row[3]
</td>
</tr>";
echo "</table>";
}
$query = " SELECT headline, date, concat (firstName,' ',lastName), body FROM "
. "school_info natural join teachers ORDER BY id_school_inf DESC LIMIT 2;";
$result = mysqli_query($conn, $query);
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^This is my query. There is a limit, so i can always fetch latest (let's say last 5) news.
Any help would be much appreciated
Upvotes: 0
Views: 58
Reputation: 360692
You need to create a separate table for every type of record you have? Simple enough, if you order
your records by the type:
SELECT * FROM whatever ORDER BY type_of_record
then
$previous = null;
while(... fetch from db ...) {
if ($row['type'] != $previous) {
... got new record type, start new table
}
... display row
$previous = $row['type']; // store current type for comparison later
}
Upvotes: 2