CODEWITHSUNDEEP
php
Trendfischer
Trendfischer

Reputation: 7632

Checking with is_array for Arrays and ArrayObjects

I have some legacy code and refactored an array to an ArrayObject. Now I have problems checking, if a variable is an array:

 if (is_array($entity) && $otherCondition) {
      // do something
 }

The function is_array() returns false on an ArrayObject. See this report.

Simplest solution would be to use something like this:

 function is_traversable($var) {
     return is_array($var) || $var instanceof Traversable;
 }

Is there some native way for PHP to do a check like this?

Upvotes: 3

Views: 1252

Answers (3)

KIKO Software
KIKO Software

Reputation: 16741

NO

is the answer to your question. An array is an array and an object is an object.

So, if you change an array to an object you should change all the checks. I don't like your is_traversable($var) function because it means you only do half a job of refactoring you code. You should replace is_array($entity) by $entity instanceof myEntityClass or is_object($entity).

In any case you should not see arrays as old fashioned. It can very well be that an array should become an object, but there's nothing wrong with arrays as such.

Upvotes: 1

Random
Random

Reputation: 3236

according to http://blog.stuartherbert.com/php/2010/07/19/should-is_array-accept-arrayobject/, you have to make the custom method you wrote in order to do what you wish...

Upvotes: 2

Cr3aHal0
Cr3aHal0

Reputation: 809

ArrayObject does contain a method named getArrayCopy() which allow you to get an array copy of your ArrayObject. I suppose that most of array built-in functions can be applied on this copy ;)

Doc : http://php.net/manual/fr/arrayobject.getarraycopy.php

Upvotes: 1

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