CODEWITHSUNDEEP
xmlforeachmule
muledevlepoer24
muledevlepoer24

Reputation: 207

Mule splitter, foreach collection using xpath3 expression

I have this Mule flow:

<file:connector name="input" doc:name="input" autoDelete="false" />
<flow name="flow1">
    <file:inbound-endpoint connector-ref="input" responseTimeout="10000" doc:name="input" path="C:\test" pollingFrequency="100000" />
    <file:filename-wildcard-filter pattern="prod.xml" />
    <set-variable variableName="tempid" value="150" doc:name="Variable" />
    <foreach doc:name="For Each" collection="#[xpath3('//marketingdetailslist/marketdetails/*', payload, 'NODESET' )]">
        <enricher source="#[flowVars.tempid]" target="#[xpath3('//marketdetails/target')]" >
        <logger message="inside  enricher ~~~~~#[message.payloadAs(java.lang.String)]"  level="INFO" doc:name="Logger"/>
        </enricher>
    </foreach>

    <logger message="after enrichment  response~~~~~~.......#[message.payloadAs(java.lang.String)]"  level="INFO" doc:name="Logger"/>

</flow>

Which receives this XML as input:

<marketingdetailslist>
       <marketdetails>
           <Jan>
               <target>100</target>
               <productname>Electronics</productname>               
           </Jan>
           <Feb>
              <target>50</target>
               <productname>Woodenitems</productname>
           </Feb>
       </marketdetails>
</marketingdetailslist>

And this would be the expected output, having the values change:

<marketingdetailslist>
       <marketdetails>
           <Jan>
               <target>150</target>
               <productname>Electronics</productname>               
           </Jan>
           <Feb>
              <target>150</target>
               <productname>Woodenitems</productname>
           </Feb>
       </marketdetails>
</marketingdetailslist>

I can't get the expected output. What would I need to change in my flow to achieve that?

Upvotes: 2

Views: 1006

Answers (1)

David Dossot
David Dossot

Reputation: 33413

It seems you are trying to emulate the XSL-T Transformer with a set of message processors. You may succeed but it would be much better to use XSL-T instead, as it is designed for performing this kind of transformation.

Upvotes: 2

Related Questions