CODEWITHSUNDEEP
pythonregexmaxlength
mquantin
mquantin

Reputation: 1158

Python regex pattern max length in re.compile?

I try to compile a big pattern with re.compile in Python 3.

The pattern I try to compile is composed of 500 small words (I want to remove them from a text). The problem is that it stops the pattern after about 18 words

Python doesn't raise any error.

What I do is: 

stoplist = map(lambda s: "\\b" + s + "\\b", stoplist)
stopstring = '|'.join(stoplist)
stopword_pattern = re.compile(stopstring)

The stopstring is ok (all the words are in) but the pattern is much shorter. It even stops in the middle of a word!

Is there a max length for the regex pattern?

Upvotes: 12

Views: 9274

Answers (1)

chepner
chepner

Reputation: 530793

Consider this example:

import re
stop_list = map(lambda s: "\\b" + str(s) + "\\b", range(1000, 2000))
stop_string = "|".join(stop_list)
stop_word_pattern = re.compile(stop_string)

If you try to print the pattern, you'll see something like:

>>> print(stop_word_pattern)
re.compile('\\b1000\\b|\\b1001\\b|\\b1002\\b|\\b1003\\b|\\b1004\\b|\\b1005\\b|\\b1006\\b|\\b1007\\b|\\b1008\\b|\\b1009\\b|\\b1010\\b|\\b1011\\b|\\b1012\\b|\\b1013\\b|\\b1014\\b|\\b1015\\b|\\b1016\\b|\\b1017\\b|\)

which seems to indicate that the pattern is incomplete. However, this just seems to be a limitation of the __repr__ and/or __str__ methods for re.compile objects. If you try to perform a match against the "missing" part of the pattern, you'll see that it still succeeds:

>>> stopword_pattern.match("1999")
<_sre.SRE_Match object; span=(0,4), match='1999')

As explained in the comments, you can return a complete pattern with .pattern, e.g.:

stopword_pattern.pattern

Upvotes: 12

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