CODEWITHSUNDEEP
pythonstringinteger
novice2020
novice2020

Reputation: 115

Printing string as integers in python 3

I'm writing a program in python 3 to convert input string to integers. There is just one problem with the code. That whenever a space comes it prints -64. I've tried editing a code but it prints -64 along with the space. Any advice?

n = input("please enter the text:").lower()

print(n)
a = []
for i in n:
    a.append(ord(i)-96)
    if (ord(i)-96) == -64:
        a.append(" ")
print(a)

Thanks

Input: "BatMan is Awesome"
Output: [2, 1, 20, 13, 1, 14, -64, ' ', 9, 19, -64, ' ', 1, 23, 5, 19, 15, 13, 5]

Upvotes: 0

Views: 85

Answers (4)

LexyStardust
LexyStardust

Reputation: 1018

You could also do this as a one(ish)-liner:

import string

n = input("please enter the text:").lower()

a = [ord(c) - 96 if c not in string.whitespace else c for c in n]
print(a)

Using the string.whitespace list also means that other types of whitespace will be kept, which might be useful to you?

Upvotes: 1

Padraic Cunningham
Padraic Cunningham

Reputation: 180411

You can check if the character is a space with str.isspace() adding ord(i)-96 if it not a space else just add the char:

n = "BatMan is Awesome".lower()

print([ord(i)-96 if not i.isspace() else i for i in n])

[2, 1, 20, 13, 1, 14, ' ', 9, 19, ' ', 1, 23, 5, 19, 15, 13, 5]

The equivalent code in your loop would be:

a = []
for i in n:
    if not i.isspace():
        a.append(ord(i)-96)
    else:
        a.append(i)

Upvotes: 2

ZdaR
ZdaR

Reputation: 22954

Actually you were appending ord(i)-96 to a before checking the condition if (ord(i)-96) == -64, So the correct way is to first check the condition and if it matches then append " " else simple append ord(i)-96, You can simply do the same with only one if condition and ignoring the else cause by reverting the conditional as :

n = input("please enter the text:").lower()

print(n)
a = []
for i in n:
    if (ord(i)-96) != -64:
        a.append(ord(i)-96)     
print(a)

Upvotes: 1

syntonym
syntonym

Reputation: 7384

If I understand you correctly you want to convert "abc def" to [1, 2, 3, " ", 4, 5, 6]. Currently you are first adding ord(i) - 96 to your list and then, if the character is a space, you add an additional space. You want only to add ord(i) - 96 if it is not a space.

n = input("please enter the text:").lower()

print(n)
a = []
for i in n:

    if (ord(i)-96) == -64:
        a.append(" ")
    else:
        a.append(ord(i)-96)
print(a)

Upvotes: 2

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