CODEWITHSUNDEEP
go
user1930848
user1930848

Reputation: 341

Reading XML with golang

I'm trying to read som XML with golang. I'm basing it on this example which works. https://gist.github.com/kwmt/6135123#file-parsetvdb-go

This is my files:

Castle0.xml

<?xml version="1.0" encoding="UTF-8" ?>
<Channel>
<Title>test</Title>
<Description>this is a test</Description>
</Channel>

test.go

package main

import (
    "encoding/xml"
    "fmt"
    "io/ioutil"
    "os"
)

type Query struct {
    Chan Channel `xml:"Channel"`
}

type Channel struct {
    title    string `xml:"Title"`
    desc string `xml:"Description"`
}


func (s Channel) String() string {
    return fmt.Sprintf("%s - %d", s.title, s.desc)
}

func main() {
    xmlFile, err := os.Open("Castle0.xml")
    if err != nil {
        fmt.Println("Error opening file:", err)
        return
    }
    defer xmlFile.Close()

    b, _ := ioutil.ReadAll(xmlFile)

    var q Query
    xml.Unmarshal(b, &q)

    fmt.Println(q.Chan)

}

Output: - %!d(string=)

Any one know what I'm doing wrong? (I'm doing this to learn go, so go easy on me :P)

Upvotes: 4

Views: 8058

Answers (1)

Ainar-G
Ainar-G

Reputation: 36199

Other packages, including encoding/json and encoding/xml can only see exported data. So firstly your title and desc should be Title and Desc correspondingly.

Secondly, you're using %d (integer) format in Sprintf when printing a string. That's why you're getting %!d(string=), which means "it's not an integer, it's a string!".

Thirdly, there is no query in your XML, so unmarshal directly into q.Chan.

This is the working example. http://play.golang.org/p/l0ImL2ID-j

Upvotes: 4

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