Reputation: 5730
I'm java virgin. I've made really simple code like below.
class TreeData implements Comparable<TreeData> {
private String sixString;
private ArrayList<Integer> stringNum = new ArrayList<Integer>();
private ArrayList<Integer> charNum = new ArrayList<Integer>();
public TreeData(String sixString, int stringNum, int charNum){
this.sixString = sixString;
(this.stringNum).add(stringNum);
(this.charNum).add(charNum);
}
public int compareTo(TreeData other) {
return sixString.compareTo(other.getSixString());
}
public String getSixString(){
return sixString;
}
}
class Child<T extends Comparable<T>>{
public void print(T data){
//error : String a = data.getSixString();
System.out.println("hi");
}
}
public class Test {
public static void main(String[] args) {
Child<TreeData> child = new Child<TreeData>();
TreeData td = new TreeData("sixString", 8, 2);
child.print(td);
}
}
I had a problem in 'print' method in the Child class. When I tried calling the getSixString() method of data(passed as argument), it occurs error. I don't know why I can't using public method in the argument 'data'. Is it related with Generic? Thanks, in advance.
Upvotes: 0
Views: 37
Reputation: 3688
In your Child class, you only define T to be extending Comparable. Yet you expect it to have the method getSixString which Comparable doesn't have. What you probably want it for it to be extending TreeData:
class Child<T extends TreeData>{
public void print(T data){
String a = data.getSixString();
//should work now since T defines getSixString()
}
}
Or better yet if all you want is for T to be TreeData, you don't need any generic class. I'm assuming your real intention was:
class Child extends TreeData {
public void print(){
String a = getSixString();
}
}
Upvotes: 1