CODEWITHSUNDEEP
javascriptvariablesobject
user3553493
user3553493

Reputation:

Replacing property name as stated in another variable

I'm not exactly sure how I should phrase it but basically I want to achieve such that object a:

var a = {
"test123": "A",
"testing/test": "B",
"notest": "C"
};

and object b:

var b = {
"test123": "Test 123",
"testing": "Testing"
};

combine such that there is an object c that looks like this:

var c = {
"Test 123": "A",
"Testing/test": "B",
"notest": "C"
};

I hope you understand what I'm talking about. Basically combine / replace objects a and b into a c such that only the text before / is replaced.

Thanks!

EDIT:

Just in case you don't get it, this is what I mean.

In object b, b['test123'] = 'Test 123' so that a['test123'] should turn into c['Test 123'] because it is changed based on b.

Also since b['testing'] = 'Testing', a['testing/test'] would turn into c['Testing/test'] as stated in b, just that the text after the / is not affected.

Upvotes: 2

Views: 53

Answers (2)

Jeff
Jeff

Reputation: 6953

This should do it:

var a = {
  "test123": "A",
  "testing/test": "B",
  "notest": "C"
};


var b = {
  "test123": "Test 123",
  "testing": "Testing"
};

var c = {}

for (prop in a) {
    //console.log(prop);

    var propParts = prop.split("/");  // only get the first part of properties with an "/" in it

    if(b.hasOwnProperty(propParts[0])) {  // if we have a new property name in b, use that
        c[b[propParts[0]]] = a[prop];
    } else {     // if not, use the one that came from object a
        c[prop] = a[prop];
    }
}

console.log(c);

Fiddle: http://jsfiddle.net/03ynxwa0/

EDIT:

I missed that you also want the "/" in the new propertyname. Please refer to yozh's answer!

Upvotes: 1

yozh
yozh

Reputation: 1223

var a = {
"test123": "A",
"testing/test": "B",
"notest": "C"
};

var b = {
"test123": "Test 123",
"testing": "Testing"
};

var c = {};
for (var p in a) {
  var prop = p.split("/")[0];

  if (b.hasOwnProperty(prop)) {
    c[p.replace(prop, b[prop])] = a[p];
  } else {
    c[p] = a[p];
  }
}
console.log(c);

http://plnkr.co/edit/Lhi5fLKkW4UBzhOK6le7?p=preview

Upvotes: 2

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