Reputation: 4801
First, I am completely new to Haskell, so sorry for the question in advance, as it might look kind of simple, but still I get this error message:
Couldn't match expected type `[a]' with actual type `a'
`a' is a rigid type variable bound by
the type signature for middle :: [a] -> a
at myFile.lhs:18:12
Relevant bindings include
xs :: [a] (bound at myFile.lhs:20:12)
x :: a (bound at myFile.lhs:20:10)
middle :: [a] -> a
(bound at myFile.lhs:19:2)
In the first argument of `(!!)', namely `x'
In the first argument of `div', namely `x !! length xs'
Failed, modules loaded: none.
While trying to load:
>middle :: [a] -> a
>middle [] = []
>middle (x:xs) = if (l `mod` 2 == 0) then xs !! (l`div` 2) - 1 else x !! l `div` 2
where l = length xs
If something is vague or unclear, please comment.
EDIT Because of the use of div I get:
Error: No instance for (Integral a) arising from a use of `div'
Possible fix:
add (Integral a) to the context of
the type signature for middle :: [a] -> a
In the expression: xs !! l `div` 2
In the expression:
if (l `mod` 2 == 0) then xs !! (l `div` 2) - 1 else xs !! l `div` 2
In an equation for `middle':
middle (x : xs)
= if (l `mod` 2 == 0) then
xs !! (l `div` 2) - 1
else
xs !! l `div` 2
where
l = length xs
Upvotes: 1
Views: 499
Reputation: 116174
Note that x
is just an element, not a list. So, using x !! anything
is a type error. Did you mean xs !! anything
instead?
Further,
middle [] = []
is wrong since you must return an element, not a list. Since there is no middle element, we can only return bottom, e.g.
middle [] = error "middle: empty list"
The above makes the function a partial one, i.e. if in a larger program you call the function with an empty list, the program will crash.
If you want to forbid that, you can change the type to Maybe
:
middle :: [a] -> Maybe a
middle [] = Nothing
middle (x:xs) = Just (.....)
Upvotes: 1