Reputation:
I've a string in a variable titled $str
as follows. This I got after converting it into JSON format. So the one more additional slash is added by JSON so please ignore it as it would not display while showing the string.
$str ="Let\\'s\nIt\\'s\nHe\\'s\nShe\\'s"; # \n is used for new line character, please ignore it
Now I want to check the presence of such backslash/es in a string and if they are present remove them and get the desired cleaned up string. In above case the output string should be(after converting it into JSON format) : "Let\'s\nIt\'s\nHe\'s\nShe\'s"
I tried below code but it didn't work out for me:
$str = br2nl(str_replace('\\','',$str));
function br2nl($buff = '') {
$buff = mb_convert_encoding($buff, 'HTML-ENTITIES', "UTF-8");
$buff = preg_replace('#<br[/\s]*>#si', "\n", $buff);
$buff = trim($buff);
return $buff;
}
Can some one please help me in this regard please?
Upvotes: 0
Views: 217
Reputation: 5450
As previously suggested, stripslashes()
is the best way to do this:
<?php
$dirty ="Let\\'s\nIt\\'s\nHe\\'s\nShe\\'s";
$clean = stripslashes($dirty);
echo $clean."\n";
?>
Output:
Let's It's He's She's
Upvotes: 1