CODEWITHSUNDEEP
javahibernatejpa
slartidan
slartidan

Reputation: 21608

How to set "mappedBy" in a subclass of an entity?

I want to split an existing JPA-Entity into a POJO superclass and an Entity subclass. I want to put the POJO superclass into a library project, that can be referenced by other projects, that do not use JPA.

My old/existing code successfully declared a OneToMany-relationship like this:

@Entity
public class Person {
    @OneToMany(mappedBy="petOwner")
    public List<Pet> pets = new ArrayList<>();
}

I want to split it into this superclass:

public class CommonPerson {
    public List<Pet> pets = new ArrayList<>();
}

The question: How could a appropriate jpa subclass look like? Can I set mappedBy in a subclass?

What I tried:

@Entity
// not possible: @AttributeOverride (has no "mappedBy" or "OneToMany")
// not possible: @AssociationOverride (has no "mappedBy" or "OneToMany")
public class JpaPerson extends CommonPerson {
}

I'm using Hibernate JPA api 2.1.

Upvotes: 2

Views: 732

Answers (2)

abentan
abentan

Reputation: 558

If you use the @Transient annotation in the MappedSuperclass method, you can use any other JPA annotation in the same method's subclass. So you can 'extend' the JPA annotations in the subclass.

Upvotes: 0

slartidan
slartidan

Reputation: 21608

Thanks @petros-splinakis !

I'm now using something like this:

@Entity
@Access(AccessType.PROPERTY)
public class JpaPerson extends CommonPerson {

    @OneToMany(mappedBy="petOwner")
    public List<Pet> getPets() {
        return pets;
    }

    public void setPets(List<Pet> pets) {
        this.pets = pets;
    }

}

And it works like a charm!

Upvotes: 1

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