CODEWITHSUNDEEP
pythonregex
user797963
user797963

Reputation: 3037

Python regex, how to search for multiple strings?

I'm new to python and am trying to figure out python regex to find any strings that match -. For example, 'type1-001' and 'type2-001' should be a match, but 'type3-asdf001' shouldn't be a match. I would like to be able to match with a regex like [type1|type2|type3]-\d+ to find any strings that start with type1, type2, or type3 and then are appended with '-' and digits. Also, it would be cool to know how to search for any upper case text appended with '-' and digits.

Here's what I think should work, but I can't seem to get it right...

pref_num = re.compile(r'[type1|type2]-\d+')

Upvotes: 0

Views: 11268

Answers (4)

Josep J.
Josep J.

Reputation: 54

[] will match any of the set of characters appearing between the brackets. To group regexes you need to use (). So, I think your regex should be something like:

pref_num = re.compile(r'(type1|type2)-\d+')

As to how to search any uppercase text appended with - and digits, I would suggest:

[A-Z]+-\d+

Upvotes: 3

lit
lit

Reputation: 16266

pref_num = re.compile(r'(type1|type2|type3)-\d+')

m = pref_num.search('type1-000')
if m != None: print(m.string)

m = pref_num.search('type2-000')
if m != None: print(m.string)

m = pref_num.search('type3-abc000')
if m != None: print(m.string)

Upvotes: 0

junnytony
junnytony

Reputation: 3535

If you only want the digit after "type" to be variable then you should put only those in the square brackets like so:

re.compile(r'type[1|2]-\d+')

Upvotes: 2

Cory Kramer
Cory Kramer

Reputation: 118011

You can use the pattern

'type[1-3]-[0-9]{3}'

Demo

>>> import re
>>> p = 'type[1-3]-[0-9]{3}'
>>> s = 'type2-005 with some text type1-101 and then type1-asdf001'
>>> re.findall(p, s)
['type2-005', 'type1-101']

Upvotes: 0

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