CODEWITHSUNDEEP
javascriptjquery
j_nobb
j_nobb

Reputation: 21

javascript code for removing last item from string if it exists

i have a code which is avaliable in the following fiddle

http://jsfiddle.net/wbagktuw/

code is like this 

<a data-rel="http://mydomain.domian.com?z_9.asp&rpttype=298&sotBy=2sortOrder=1&pagenum=2">

$(document).ready(function() {
    var urlval = $("a").attr('data-rel');
    alert(urlval);
});

i am trying to remove the &pagenum=2 from the url if it exists, if it does not exists, then no problem, if exists, i want to remove that

what should i try here

Upvotes: 2

Views: 96

Answers (4)

znap026
znap026

Reputation: 439

How about this, fiddle

  $(document).ready(function() {
    var urlval = $("a").attr('data-rel');
    var length = urlval.length
    var start = urlval.indexOf("&pagenum=");

    if (start !== -1){
        var next = urlval.indexOf("&",start+1);
        next = (next !== -1)?next:length;
        var res = urlval.substring(start, next);
        urlval = urlval.replace(res, '');
    }
    alert(urlval);
});

Upvotes: 0

Rick Hitchcock
Rick Hitchcock

Reputation: 35670

Use a regular expression to replace &pagenum= followed by any number of digits.

Also check for the case where pagenum is the first parameter, in which case it follows a question mark instead of an ampersand:

var urlval = $('a').attr('data-rel').replace(/[\?&]pagenum=\d*/g, '');

Upvotes: 4

Dan Moldovan
Dan Moldovan

Reputation: 3591

Or even better, why not just use what JS already has built-in..

urlval = urlval.replace('&pagenum=2', '');

This will handle both the cases where &pagenum=2 is present and not

Upvotes: 0

user3227295
user3227295

Reputation: 2156

use this code

 $(document).ready(function() {
    var urlval = $("a").attr('data-rel');
    if(urlval.indexOf("pagenum")>-1){

     urlval=urlval.slice(0,urlval.lastIndexOf("&"));
    console.log(urlval);

    }
});

jsfiddle http://jsfiddle.net/wbagktuw/2/

Upvotes: 0

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