Reputation: 1149
I'm trying to read out my text file line by line
FILE *infile;
char line[1000];
infile = fopen("file.txt","r");
while(fgets(line,1000,infile) != NULL)
{
//....
}
fclose(infile);
And then I need to find a specific word, for example "the", and need to see how many time it occurs and what lines it also occurs on.
I should be able to count the words with this
int wordTimes = 0;
if((strcmp("the", currentWord) == 0))
{
printf("'%s' appears in line %d which is: \n%s\n\n", "the", line_num, line);
wordTimes++;
}
where line
is the line of text that the string occurs on and line_num
is the line number that it occurs on.
And then the amount of times the word is shown uses this code:
if(wordTimes > 0)
{
printf("'%s' appears %d times\n", "the", wordTimes);
}
else
{
printf("'%s' does not appear\n", "the");
}
The problem is that I'm not sure how to compare each word in the line to "the" and still print out the line it applies on.
I have to use very basic C for this, so that means I can't use strtok()
or strstr()
. I can only use strlen()
and strcmp()
.
Upvotes: 2
Views: 1446
Reputation: 754790
Maybe you need to write a strword()
function like this. I'm assuming you can use the classification functions (macros) from <ctype.h>
, but there are workarounds if that isn't allowed either.
#include <assert.h>
#include <ctype.h>
#include <stdio.h>
char *strword(char *haystack, char *needle);
char *strword(char *haystack, char *needle)
{
char *pos = haystack;
char old_ch = ' ';
while (*pos != '\0')
{
if (!isalpha(old_ch) && *pos == *needle)
{
char *txt = pos + 1;
char *str = needle + 1;
while (*txt == *str)
{
if (*str == '\0')
return pos; // Exact match at end of haystack
txt++, str++;
}
if (*str == '\0' && !isalpha(*txt))
return pos;
}
old_ch = *pos++;
}
return 0;
}
int main(void)
{
/*
** Note that 'the' appears in the haystack as a prefix to a word,
** wholly contained in a word, and at the end of a word - and is not
** counted in any of those places. And punctuation is OK.
*/
char haystack[] =
"the way to blithely count the occurrences (tithe)"
" of 'the' in their line is the";
char needle[] = "the";
char *curpos = haystack;
char *word;
int count = 0;
while ((word = strword(curpos, needle)) != 0)
{
count++;
printf("Found <%s> at [%.20s]\n", needle, word);
curpos = word + 1;
}
printf("Found %d occurrences of <%s> in [%s]\n", count, needle, haystack);
assert(strword("the", "the") != 0);
assert(strword("th", "the") == 0);
assert(strword("t", "t") != 0);
assert(strword("", "t") == 0);
assert(strword("if t fi", "t") != 0);
assert(strword("if t fi", "") == 0);
return 0;
}
When run, this produces:
Found <the> at [the way to blithely ]
Found <the> at [the occurrences (tit]
Found <the> at [the' in their line i]
Found <the> at [the]
Found 4 occurrences of <the> in [the way to blithely count the occurrences (tithe) of 'the' in their line is the]
Is there a way to do the
strword
function without<ctype.h>
?
Yes. I said as much in the opening paragraph. Since the only function/macro used is isalpha()
, you can make some assumptions (that you're not on a system using EBCDIC) so that the Latin alphabet is contiguous, and you can use this is_alpha()
in place of isalpha()
— and omit <ctype.h>
from the list of included headers:
static inline int is_alpha(int c)
{
return (c >= 'A' && c <= 'Z') || (c >= 'a' && c <= 'z');
}
Upvotes: 4