CODEWITHSUNDEEP
scalaplayframework
agusgambina
agusgambina

Reputation: 6679

Playframework Scala Transform Request from Json to x-www-form-urlencoded

Hi I am new to Scala and Playframework. I am getting an ajax request that is json format and I need to make another request to another server with x-www-form-urlencoded format.

I have this code in the controller

  def getToken = Action.async(parse.json) { request =>
    WS.url("https://api.xxxx.com/v1/yyyy")
      .withHeaders(
        "accept" -> "application/json",
        "content-type" -> "application/x-www-form-urlencoded",
        "Authorization" -> "Auth %s".format(apiKey)
      ).post(request.body) map { response =>
        Logger.info("response from get user: " +  Json.prettyPrint(response.json))
        Ok("ok")
    }
  }

I tried different ways but I can't get this working. Maybe I should do a formatter in the model. Which would be the best way to cast the request json to a request x-www-form-urlencoded?

thank you

Upvotes: 0

Views: 1966

Answers (1)

Nader Ghanbari
Nader Ghanbari

Reputation: 4300

Short Answer

You just need to pass a Map[String, Seq[String]] to the post method. If you have some keys and values you can easily construct such a Map.

For instance:

WS.url(url).post(Map("key1" -> Seq("value1"), "key2" -> Seq("value2")))

Details

As mentioned in Form Submission section of Play WS docs, if you want to submit a form you have to pass a Map[String, Seq[String]] to the post method.

What you are passing here, instead, is a JsValue (because the request.body is of type JsValue because of the body parser type which is parser.json). So first you have to extract the set of key/value pairs from the json object and then construct a Map[String, Seq[String]] from it and pass it to post method.

For example if you are sure that the json object (extracted from the request body by body parser) is a JSON Object (not an Array or String or a Numeric Value) you can construct the needed Map easily (just for the first level key/value pairs):

def getToken = Action.async(parse.json) { request =>
  import play.api.libs.json.JsObject
  val json = request.body.as[JsObject]
  val formParamsMap = json.value.mapValues(_.asOpt[String].toSeq)
  WS.url("https://api.xxxx.com/v1/yyyy")
    .withHeaders(
      "accept" -> "application/json",
      "content-type" -> "application/x-www-form-urlencoded",
      "Authorization" -> "Auth %s".format(apiKey)
    )
    .post(formParamsMap) map { response =>
  Ok("ok")
  }
}

Upvotes: 3

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