Reputation: 331
I would like the be able to cycle backwards and forward through multiple arrays, I've only been able to make it cycle forward, but not backwards.
Here is where I am so far. (You'll notice the down arrow button is not working)
Any insight would be welcomed!
HTML
<div class="container">
<button class="btn-down">v</button>
CUSTOM HOURS
<button class="btn-up">^</button>
<p class="price-select">1200</p>
<p class="hours-select">3</p>
<p class="photos-select">200-400+</p>
<p class="postproduction-select">15</p>
</div>
<div class="weekend-notice">Note: Weekend bookings available at a minimum of 5 hours.</div>
jQuery
//FOR CUSTOM HOURS BUTTON
var price = ["1400", "1600", "1800", "2000", "2200", "1200"];
var hours = ["4", "5", "6", "7", "10", "3"];
var photos = ["400-600+", "600-800+", "800-1000+", "1000-1200+", "1200-1400+", "200-400+"];
var editing = ["17", "19", "22", "25", "30", "15"];
var i = 0;
$(".btn-up").on('click', function() {
$(".price-select").hide().html(price[i]).fadeIn(300);
$(".hours-select").hide().html(hours[i]).fadeIn(300);
$(".photos-select").hide().html(photos[i]).fadeIn(300);
$(".postproduction-select").hide().html(editing[i]).fadeIn(300);
i++;
i = i % 6;
var checkHours = parseInt($('.hours-select').text());
var weekendNotice = $('.weekend-notice');
var hoursNotice = $('.morehours-notice');
if(checkHours <= 4){
weekendNotice.fadeIn(500);
}else{
weekendNotice.fadeOut(500);
};
});
Upvotes: 3
Views: 714
Reputation: 1
Try utilizing button
selector , single click
handler increment , decrement i
based on e.target
of event
// FOR CUSTOM HOURS BUTTON
var price = ["1400", "1600", "1800", "2000", "2200", "1200"];
var hours = ["4", "5", "6", "7", "10", "3"];
var photos = ["400-600+", "600-800+", "800-1000+"
, "1000-1200+", "1200-1400+", "200-400+"];
var editing = ["17", "19", "22", "25", "30", "15"];
var i = price.length - 1;
$("button").on('click', function(e) {
if ($(e.target).is(".btn-up")) {
i = i === price.length - 1 ? 0 : ++i;
} else {
if ($(e.target).is(".btn-down")) {
i = i > 0 ? --i : price.length - 1;
};
};
$(".price-select").hide().html(price[i]).fadeIn(300);
$(".hours-select").hide().html(hours[i]).fadeIn(300);
$(".photos-select").hide().html(photos[i]).fadeIn(300);
$(".postproduction-select").hide().html(editing[i]).fadeIn(300);
var checkHours = parseInt($('.hours-select').text());
var weekendNotice = $('.weekend-notice');
var hoursNotice = $('.morehours-notice');
if (checkHours <= 4) {
weekendNotice.fadeIn(500);
} else {
weekendNotice.fadeOut(500);
};
});
p {
display: block;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js">
</script>
<div class="container">
<button class="btn-down">v</button>CUSTOM HOURS
<button class="btn-up">^</button>
<p class="price-select">1200</p>
<p class="hours-select">3</p>
<p class="photos-select">200-400+</p>
<p class="postproduction-select">15</p>
</div>
<div class="weekend-notice">Note: Weekend bookings available at a minimum of 5 hours.</div>
jsfiddle http://jsfiddle.net/4pbq4ddx/14/
Upvotes: 0
Reputation: 19288
It's possible to calculate the index for the "up" and "down" actions in one line, and coding this can be made easier by first setting data values of 1
and -1
on the up/down buttons.
It is also better practice to initialise via the script rather than hard-code in HTML.
//FOR CUSTOM HOURS BUTTON
var price = ["1400", "1600", "1800", "2000", "2200", "1200"];
var hours = ["4", "5", "6", "7", "10", "3"];
var photos = ["400-600+", "600-800+", "800-1000+", "1000-1200+", "1200-1400+", "200-400+"];
var editing = ["17", "19", "22", "25", "30", "15"];
var i = 0,
n = hours.length; // 6
$(".btn-up").data('dir', 1);
$(".btn-down").data('dir', -1);
$(".btn-up, .btn-down").on('click', function() {
// ***** this line handles both directions *****
i = (i + $(this).data('dir') + n) % n;
// ***** ********************************* *****
$(".price-select").hide().html(price[i]).fadeIn(300);
$(".hours-select").hide().html(hours[i]).fadeIn(300);
$(".photos-select").hide().html(photos[i]).fadeIn(300);
$(".postproduction-select").hide().html(editing[i]).fadeIn(300);
if(parseInt(hours[i]) <= 4) {
$('.weekend-notice').fadeIn(500);
} else {
$('.weekend-notice').fadeOut(500);
};
});
$(".btn-down").trigger('click'); //initialize
Upvotes: 3
Reputation: 33618
Start with index = -1
and iterate forward like this
i = (i+1) % (price.length);
(I used one of the arrays as a reference for length)
and backward like this
if (i <= 0) {
i = price.length - 1;
} else {
--i;
}
I think it is important where you place them.
var i = -1;
$(".btn-up").on('click', function () {
i = (i+1) % (price.length);
$(".price-select").hide().html(price[i]).fadeIn(300);
$(".hours-select").hide().html(hours[i]).fadeIn(300);
$(".photos-select").hide().html(photos[i]).fadeIn(300);
$(".postproduction-select").hide().html(editing[i]).fadeIn(300);
var checkHours = parseInt($('.hours-select').text());
var weekendNotice = $('.weekend-notice');
var hoursNotice = $('.morehours-notice');
if (checkHours <= 4) {
weekendNotice.fadeIn(500);
} else {
weekendNotice.fadeOut(500);
};
});
$(".btn-down").on('click', function () {
if (i <= 0) {
i = price.length - 1;
} else {
--i;
}
$(".price-select").hide().html(price[i]).fadeIn(300);
$(".hours-select").hide().html(hours[i]).fadeIn(300);
$(".photos-select").hide().html(photos[i]).fadeIn(300);
$(".postproduction-select").hide().html(editing[i]).fadeIn(300);
var checkHours = parseInt($('.hours-select').text());
var weekendNotice = $('.weekend-notice');
var hoursNotice = $('.morehours-notice');
if (checkHours <= 4) {
weekendNotice.fadeIn(500);
} else {
weekendNotice.fadeOut(500);
};
});
Here is a demo http://jsfiddle.net/dhirajbodicherla/4pbq4ddx/10/
Upvotes: 1
Reputation: 3230
$(".btn-down").on('click', function() {
$(".price-select").hide().html(price[i]).fadeIn(300);
$(".hours-select").hide().html(hours[i]).fadeIn(300);
$(".photos-select").hide().html(photos[i]).fadeIn(300);
$(".postproduction-select").hide().html(editing[i]).fadeIn(300);
if(i == 0) {
i = 5
} else {
i--;
}
var checkHours = parseInt($('.hours-select').text());
var weekendNotice = $('.weekend-notice');
var hoursNotice = $('.morehours-notice');
if(checkHours <= 4){
weekendNotice.fadeIn(500);
}else{
weekendNotice.fadeOut(500);
};
});
Upvotes: 1