CODEWITHSUNDEEP
arraysmatlabfunctionmatrix
owner
owner

Reputation: 743

function handle and array operators - Matlab

I keep getting a matrix dimension error, although i pay attention to the array operators from the below code. As I am not willing to strictly perform matrix operations could someone explain the origin of the dimension / size issue?

Thanks

Error using .* Matrix dimensions must agree 

% integrand behaviour
f=@(k) k .* exp(-k);
x=0.5;
al=1;
bet=0.89;
theta0=(1/al) .*atan(bet .*tan(pi*al/2));
c=exp(-(pi .* x) ./2 * bet);
c2=1 /(2.*abs(bet));
v1=@(theta) 2/pi .* ((pi/2 + bet.*theta)/cos(theta)) .* exp(1/bet .* (pi/2 +
bet.*theta)...
.* tan(theta));
g=@(theta) c .* v1(theta);
y=@(theta) f(g(theta)) ;     % values of integrand
a=[-pi/2:0.2:pi/2]';
Y=y(a);
plot(a,Y)

Upvotes: 0

Views: 39

Answers (1)

Tamás Szabó
Tamás Szabó

Reputation: 733

The source of your problem is here:

(pi/2 + bet.*theta)/cos(theta)

You use the / operator, where I think that you mean to use the ./ operator.

Upvotes: 1

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