Reputation: 152637
$(document).ready(function(){
$('#content1').hide();
$('a#open').click(function(){
$('#content1').show('slow');
});
$('a#close').click(function(){
$('#content1').hide('slow');
})
});
in this code of toogle open and close button is different
<a>
and <a id="close">
I want to make same button <a>
for open and close and want to give different background image for open and close position
Upvotes: 0
Views: 2728
Reputation: 2987
$('a').click(function(){
$('#content1').slideToggle();
});
If you would like to change their css ,you can re-write it in the following way.
$('a').click(function(){
if ($('#content1').is(":visible"))
{
//change your css here
//for eg. $(#content1).css('background-image', first_image);
$('#content1').hide('slow');
}
else{
//change your css here
//for eg. $(#content1).css('background-image', second_image);
$('#content1').show('slow');
}
});
Upvotes: 6
Reputation: 67194
Check out this jsFiddle I made a while ago. (With a lot of help from SO)
Hopefully this is what you're looking for.
Hope it helps.
Upvotes: 0
Reputation: 52932
Make your own function called ShowOrHide() and call that when the button is clicked.
In ShowOrHide, see if the div is already visible/hidden and do the opposite.
Then you'll only need one button to perform both operations.
Upvotes: 0