Tuple unpacking in function arguement

Question

In the following function, args[i] should unpack into the arguments of the function func via the * before it, however what gets passed in is a list. What am I missing?

def mymap(func, *seq):
    args = list(zip(seq))
    ret = []
    for i in range(len(args)):
        print(type(args[i]))
        ret.append( func(*args[i]) )
    return ret

f = lambda x: x+2

mymap(f, [1,2,3])

Answer 1

The * packs in a function definition and unpacks in a function call.

Defining a new function:

def func1(*args):
    print(args)

this packs:

>>> func1(1, 2)
(1, 2)

A function with two parameters

def func2(a, b):
    print(a)
    print(b)

can be called with a sequence using the *:

>>> func2(*[1, 2])
1
2