CODEWITHSUNDEEP
rubyregex
tomtom
tomtom

Reputation: 1190

Regular expression query to pull out last piece of matching data

I have a specific RegEx question, simply because I'm wracking my brain trying to isolate one item, rather than multiple.

Here is my text I am searching: 

"{\"1430156203913\"=>\"ABC\", \"1430156218698\"=>\"DEF\", \"1430156219763\"=>\"GHI\", \"1430156553620\"=>\"JKL", \"1430156793764\"=>\"MNO\", \"1430156799454\"=>\"PQR\"}"

What I would like to do is capture the key associated with ABC as well as the key associated with GHI

The first is easy enough, and I'm capturing it with this RegEx:
/\d.*ABC/ maps to: "1430156203913\"=>\"ABC.
Then, I'd just use /\d/ to pull out the 1430156203913 key that I'm looking for.

The second is what I'm having difficulty with.

This does not work:
/\d.*GHI/ maps to the start of the first digit to my final string (GHI) ->
1430156203913\"=>\"ABC\", \"1430156218698\"=>\"DEF\", \"1430156219763\"=>\"GHI

Question: How can I edit this second Regex to just capture 1430156219763?

Upvotes: 0

Views: 52

Answers (4)

Cary Swoveland
Cary Swoveland

Reputation: 110675

This is one way you could do that:

def extract(str, key)
  r = /
      (?<=\")   # match \" in a positive lookbehind
      \d+       # match one or more digits
      (?=       # begin a positive lookahead
        \"=>\"  # match \"=>\"
        #{key}  # match value of key
        \"      # match \" 
      )         # end positive lookahead
      /x

  str[r]
end

extract str, "ABC" #=> "1430156203913" 
extract str, "GHI" #=> "1430156219763"

Upvotes: 1

Nader Hisham
Nader Hisham

Reputation: 5414

Try this one to capture only the key 

\b\d+\b(?=\\"=>\\"GHI)

check this Demo

Notice I've added \b around d+ just for a better perfromance

Upvotes: 1

AJcodez
AJcodez

Reputation: 34156

To capture all the keys and values, use String#scan.

pairs = s.scan /"(\d+)"=>"([[:upper:]]+)"/
# [["1430156203913", "ABC"],
#  ["1430156218698", "DEF"],
#  ["1430156219763", "GHI"],
#  ["1430156553620", "JKL"],
#  ["1430156793764", "MNO"],
#  ["1430156799454", "PQR"]]

Then to get any k/v pair you want, hashify and find them.

Hash[pairs].invert.values_at('ABC', 'DEF')
# ["1430156203913", "1430156218698"]

Upvotes: 1

vks
vks

Reputation: 67968

\d[^,]*GHI

You can simply use this.See demo.

https://regex101.com/r/yW3oJ9/3

Upvotes: 1

Related Questions