Reputation: 159
My goal is to find the date of a particular day in a given week of that month. Say for example, I want to know the date on May 2nd week's Friday. I can get the following via Time and Date classes.
Week number of current year (considering Sunday as first)
Time.strftime(%U)
Day of the week (0..7)
Time.strftime(%w)
But how I get the what week (1st,2nd,3rd,4th or 5th) of the month it is in?
Thanks in advance!
Upvotes: 3
Views: 4728
Reputation: 9369
I think the dependency free version would be:
def week_of_month date
first_of_month = Date.new(date.year, date.month, 1)
partial_first_week = date.cwday >= first_of_month.cwday ? 1 : 0
(date.cweek - first_of_month.cweek) + partial_first_week
end
Upvotes: -1
Reputation: 593
There is a cool way to calc it in Rails:
dt.cweek - dt.beginning_of_month.cweek + 1
Upvotes: -1
Reputation: 1
def number_of_weeks_month(start_of_month, count, end_of_month)
if start_date > end_of_month
return count
else
number_of_weeks_month(start_date.end_of_week + 1, count + 1, end_of_month)
end
end
number_of_weeks_month(Date.parse("2017-11-01"),0,Date.parse("2017-11-30"))
for the month on November it gives 4
Upvotes: 0
Reputation: 510
In order to handle the requirements you listed, I would suggest writing a helper function to get the number of the week in a month.
def get_month_week(date_or_time, start_day = :sunday)
date = date_or_time.to_date
week_start_format = start_day == :sunday ? '%U' : '%W'
month_week_start = Date.new(date.year, date.month, 1)
month_week_start_num = month_week_start.strftime(week_start_format).to_i
month_week_start_num += 1 if month_week_start.wday > 4 # Skip first week if doesn't contain a Thursday
month_week_index = date.strftime(week_start_format).to_i - month_week_start_num
month_week_index + 1 # Add 1 so that first week is 1 and not 0
end
This can then just be called like so:
get_month_week(Date.today)
If you really feel like monkey-patching is something you want, you can add to the Date class:
class Date
def month_week(start_day = :sunday)
week_start_format = start_day == :sunday ? '%U' : '%W'
month_week_start = Date.new(self.year, self.month, 1)
month_week_start_num = month_week_start.strftime(week_start_format).to_i
month_week_start_num += 1 if month_week_start.wday > 4 # Skip first week if doesn't contain a Thursday
month_week_index = self.strftime(week_start_format).to_i - month_week_start_num
month_week_index + 1 # Add 1 so that first week is 1 and not 0
end
end
And this can be called on a date or time like so:
Date.today.month_week
or
Time.current.to_date.month_week
I would advise against this since it may collide with other libraries or violate least-surprise for other developers working on the project.
Upvotes: 3
Reputation: 186
You can try this:
current_time = Time.zone.now
beginning_of_the_month = current_time.beginning_of_month
puts current_time.strftime('%U').to_i - beginning_of_the_month.strftime('%U').to_i + 1
Or
Time.parse('2015-01-08').strftime('%U').to_i - Time.parse('2015-01-01').strftime('%U').to_i + 1
Upvotes: 3
Reputation: 24337
The week-of-month gem will do this. First add the gem to your Gemfile:
gem 'week_of_month'
Then use it like:
Time.now.week_of_month
If you need the week to start on Monday instead of Sunday. Stick this in an initializer:
WeekOfMonth.configuration.monday_active = true
Upvotes: 1