CODEWITHSUNDEEP
pythonffmpegsubprocess
Hyperion
Hyperion

Reputation: 2625

ffmpeg subprocess fail to open on OS X

I've got this script:

PATH = os.path.dirname(os.path.abspath(__file__))


global TEMP
for video in os.listdir(VIDEOS):
    ffmpeg = PATH + "/ffmpeg/ffmpeg"
    arg1 = " -v 0 -i "
    arg2 = VIDEOS + "/" + video
    arg3 = " -r 1 -f image2 "
    arg4 = TEMP + "/" + os.path.splitext(video)[0] + "-%d.jpg"
    subprocess.Popen(ffmpeg + arg1 + arg2 + arg3 + arg4).wait()

that works perfectly on Windows (using ffmpeg.exe of course), but when I try to run it on Mac I got error: 

  File "/Users/francesco/Desktop/untitled0.py", line 20, in Main
    subprocess.Popen(ffmpeg + arg1 + arg2 + arg3 + arg4).wait()

  File "subprocess.pyc", line 710, in __init__

  File "subprocess.pyc", line 1327, in _execute_child

OSError: [Errno 2] No such file or directory

I've tried to print ffmpeg + arg1 + arg2 + arg3 + arg4 and paste it manually in the terminal, nothing happens, it just stuck, but if I try to copy manually all the printed arguments, it works.

Upvotes: 1

Views: 615

Answers (3)

user3127882
user3127882

Reputation: 522

Had the same problem. Python 3.7 and ffmpeg, both installed with brew. Just like for you, worked in terminal, but not as a (CRON) script. Turned out that the problem was not specifying the full PATH for ffmpeg, which in my case is "/usr/local/Cellar/ffmpeg/4.1.3/bin/ffmpeg". So

[...]

import os

theCommand = "/usr/local/Cellar/ffmpeg/4.1.3/bin/ffmpeg -i /Volumes/ramDisk/audio.mp4 -i /Volumes/ramDisk/video.mp4 -c:a copy -c:v copy /Volumes/ArchiveDisk/final.mp4" 
os.system(theCommand)

Upvotes: 0

Padraic Cunningham
Padraic Cunningham

Reputation: 180391

Pass a list of args and use check_call if you want to wait until the process returns:

from subprocess import check_call
for video in os.listdir(VIDEOS):
    check_call(["ffmpeg","-v", "0", "-i","{}/{}".format(VIDEOS,video), "-r", "1", "-f",
                "image2","{}/-%d.jpg".format(TEMP), os.path.splitext(video)[0]])

check_call will raise a CalledProcessError for any non-zero exit status

Upvotes: 0

dlask
dlask

Reputation: 8982

The subprocess.Popen requires list of strings, something like [ffmpeg, arg1, ...].

This command fails on Linux:

subprocess.Popen("ls -la").wait()

while this one succeeds:

subprocess.Popen(["ls", "-la"]).wait()

Upvotes: 2

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