CODEWITHSUNDEEP
pythonlistprintingcoding-style
Blitva
Blitva

Reputation: 191

Can I print list data in a more elegant way?

Is there a cleaner way to structure my print function?

lloyd = {
    "name": "Lloyd",
    "homework": [90.0, 97.0, 75.0, 92.0],
    "quizzes": [88.0, 40.0, 94.0],
    "tests": [75.0, 90.0]
    }
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
    }
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
    }

students = [lloyd, alice, tyler]

for student in students:
    print student["name"]
    print student["homework"]
    print student["quizzes"]
    print student["tests"]

I tried the following piece of code but got a syntax error:

for student in students:
    print student["name", "homework", "quizzes", "tests"]

I apologize if this has already been answered, but I couldn't find the question.

Upvotes: 3

Views: 106

Answers (2)

Padraic Cunningham
Padraic Cunningham

Reputation: 180411

You can pass each dict to str.format accessing arguments by name:

for student in students:
    print("{name}\n{homework}\n{quizzes}\n{tests}".format(**student))

Output:

Lloyd
[90.0, 97.0, 75.0, 92.0]
[88.0, 40.0, 94.0]
[75.0, 90.0]
Alice
[100.0, 92.0, 98.0, 100.0]
[82.0, 83.0, 91.0]
[89.0, 97.0]
Tyler
[0.0, 87.0, 75.0, 22.0]
[0.0, 75.0, 78.0]
[100.0, 100.0]

Upvotes: 2

arshajii
arshajii

Reputation: 129507

I would just use a second for loop:

for student in students:
    for x in ("name", "homework", "quizzes", "tests"):
        print student[x]

Upvotes: 3

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