CODEWITHSUNDEEP
javaspring-mvctomcat
lhao0301
lhao0301

Reputation: 2011

How to publish java web project in tomcat

To publish one java-web application in tomcat, I copy the project that named 'demo-mvc' to the tomcat's webapps folder.Then I visit "http://localhost:8080/demo-mvc/xx.jsp" in the chorme browser after starting tomcat but it prompts "The requested resource is not available".I tried editing the server.xml as follows

<Context docBase="D:\apache-tomcat-7.0.57\webapps\demo-mvc" path="/demo-mvc" reloadable="true" source="org.eclipse.jst.jee.server:website"/>

Finally it still does no effect.I am confused about where the problem is.

Upvotes: 0

Views: 304

Answers (1)

Make
Make

Reputation: 422

Try to clean your project from Project clean option and make sure you are mapping all your resources

In your web.xml the code should be like this:

    <?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

    <!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/root-context.xml</param-value>
    </context-param>

    <!-- Creates the Spring Container shared by all Servlets and Filters -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <!-- Processes application requests -->
    <servlet>
        <servlet-name>appServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>appServlet</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

</web-app>

Upvotes: 1

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