CODEWITHSUNDEEP
pythonpython-3.xfilepathos.path
fnkr
fnkr

Reputation: 10075

Python os.path.basename, strip parameters

How do I find out the basename of the file in this case?

>>> from os.path import basename
>>> basename('C:\\test.exe --help')
'test.exe --help'

Result should be just test.exe without --help or any other arguments.

Upvotes: 0

Views: 1073

Answers (3)

myaut
myaut

Reputation: 11504

There is shlex module that mimics behaviour of a Unix shell (but since command.com used to mimic some of its features, it should work too). It'll also will tolerate a quotes (but note that I used raw strings in example):

>>> import shlex
>>> print shlex.split(r'C:\\test.exe --help')
['C:\\test.exe', '--help']
>>> print shlex.split(r'"C:\\test.exe" --help')
['C:\\test.exe', '--help']
>>> print shlex.split(r'"C:\\Program Files\\test.exe" --help')
['C:\\Program Files\\test.exe', '--help']

So take first string returned from shlex.split, and pass to basename.

If you want to get rid of treating backslashes \ as escape sequences, you should construct shlex object explicitly:

>>> from shlex import shlex
>>> lex = shlex('C:\\test.exe --help')
>>> lex.whitespace_split = True
>>> lex.escape = ''
>>> list(lex)
['C:\\test.exe', '--help']

Upvotes: 1

coder3521
coder3521

Reputation: 2646

import os, shlex
print(os.path.basename(shlex.split(r'"C:\\test.exe" --help')[0]))

Upvotes: 0

Visgean Skeloru
Visgean Skeloru

Reputation: 2263

Well the problem is that, at least on Linux, 'test.exe --exe' is a valid filename. So that is the reason why python does not try to clean filenames from 'parameters'. I looked at windows docs and it looks like you also make file named 'test.exe --exe'. So, it really depends on what you are trying to achieve.

Also have a look at this: What is the most correct regular expression for a UNIX file path?

You should then probably check if file exists, if it does not then use regular expression or the shlex module to strip the parameters...

Upvotes: 1

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