CODEWITHSUNDEEP
phpdatedateinterval
Samuel Auger
Samuel Auger

Reputation: 262

Substract a DateInterval from another DateInterval

$date1 = new DateInterval('PT100S'); //100 seconds
$date2 = new DateInterval('PT20S');  //20 seconds

How to make $date1 - $date2? I've searched on google for hours.

Upvotes: 2

Views: 456

Answers (2)

Rizier123
Rizier123

Reputation: 59701

This should work for you:

Here I simply get the array_intersect_key() from the defined $keys, with both DateInterval objects. So that I then can loop through both arrays with array_map() and subtract the values. With the calculated values I create a new DateInterval object, which I then return.

<?php

    $date1 = new DateInterval('PT100S');
    $date2 = new DateInterval('PT20S'); 

    function subtractDateIntervals($intervalOne, $intervalTwo) {
        $keys = ["y", "m", "d", "h", "i", "s"];

        $intervalArrayOne = array_intersect_key((array)$intervalOne, array_flip($keys));
        $intervalArrayTwo = array_intersect_key((array)$intervalTwo, array_flip($keys));

        $result = array_map(function($v1, $v2){
            return abs($v1 - $v2);
        }, $intervalArrayOne, $intervalArrayTwo);

        return new DateInterval(vsprintf("P%dY%dM%dDT%dH%dM%dS", $result));


    }       

    var_dump(subtractDateIntervals($date1, $date2));

?>

output:

object(DateInterval)#3 (15) {
  //...
  ["s"]=>
  int(80)
  //...
}

Upvotes: 1

Federkun
Federkun

Reputation: 36964

Use format to get the number of seconds, then do the subtraction.

echo $date1->format('%s') - $date2->format('%s');

Is this what you wanted?

Upvotes: 2

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