Reputation: 12953
How do I get the equivalents of SQLite's interactive shell commands .tables
and .dump
using the Python sqlite3 API?
Upvotes: 212
Views: 302997
Reputation: 4127
Python 2 program to print table names and the column names for those tables:
import sqlite3
db_filename = 'database.sqlite'
newline_indent = '\n '
db=sqlite3.connect(db_filename)
db.text_factory = str
cur = db.cursor()
result = cur.execute("SELECT name FROM sqlite_master WHERE type='table';").fetchall()
table_names = sorted(zip(*result)[0])
print "\ntables are:"+newline_indent+newline_indent.join(table_names)
for table_name in table_names:
result = cur.execute("PRAGMA table_info('%s')" % table_name).fetchall()
column_names = zip(*result)[1]
print ("\ncolumn names for %s:" % table_name)+newline_indent+(newline_indent.join(column_names))
db.close()
print "\nexiting."
Python 3 version:
import sqlite3
db_filename = 'database.sqlite'
newline_indent = '\n '
db=sqlite3.connect(db_filename)
db.text_factory = str
cur = db.cursor()
result = cur.execute("SELECT name FROM sqlite_master WHERE type='table';").fetchall()
table_names = sorted(list(zip(*result))[0])
print ("\ntables are:"+newline_indent+newline_indent.join(table_names))
for table_name in table_names:
result = cur.execute("PRAGMA table_info('%s')" % table_name).fetchall()
column_names = list(zip(*result))[1]
print (("\ncolumn names for %s:" % table_name)
+newline_indent
+(newline_indent.join(column_names)))
db.close()
print ("\nexiting.")
Upvotes: 31
Reputation: 16776
In Python:
import sqlit3
con = sqlite3.connect('database.db')
cursor = con.cursor()
cursor.execute("SELECT name FROM sqlite_master WHERE type='table';")
print(cursor.fetchall())
Watch out for my other answer. There is a much faster way using pandas.
Upvotes: 348
Reputation: 91
Some might find my function useful if you just want to print out all of the tables and columns in your db.
In the loop, I query each TABLE with LIMIT 0 so it just returns the header info without all the data. You make an empty df out of it, and use the iterable df.columns to print each column name out.
conn = sqlite3.connect('example.db')
c = conn.cursor()
def table_info(c, conn):
'''
prints out all of the columns of every table in db
c : cursor object
conn : database connection object
'''
tables = c.execute("SELECT name FROM sqlite_master WHERE type='table';").fetchall()
for table_name in tables:
table_name = table_name[0] # tables is a list of single item tuples
table = pd.read_sql_query("SELECT * from {} LIMIT 0".format(table_name), conn)
print(table_name)
for col in table.columns:
print('\t' + col)
print()
table_info(c, conn)
Results will be:
table1
column1
column2
table2
column1
column2
column3
etc.
Upvotes: 9
Reputation: 2386
If someone wants to do the same thing with Pandas
import pandas as pd
import sqlite3
conn = sqlite3.connect("db.sqlite3")
table = pd.read_sql_query("SELECT name FROM sqlite_master WHERE type='table'", conn)
print(table)
Upvotes: 28
Reputation: 16776
The FASTEST way of doing this in python is using Pandas (version 0.16 and up).
Dump one table:
db = sqlite3.connect('database.db')
table = pd.read_sql_query("SELECT * from table_name", db)
table.to_csv(table_name + '.csv', index_label='index')
Dump all tables:
import sqlite3
import pandas as pd
def to_csv():
db = sqlite3.connect('database.db')
cursor = db.cursor()
cursor.execute("SELECT name FROM sqlite_master WHERE type='table';")
tables = cursor.fetchall()
for table_name in tables:
table_name = table_name[0]
table = pd.read_sql_query("SELECT * from %s" % table_name, db)
table.to_csv(table_name + '.csv', index_label='index')
cursor.close()
db.close()
Upvotes: 96
Reputation: 21
#!/usr/bin/env python
# -*- coding: utf-8 -*-
if __name__ == "__main__":
import sqlite3
dbname = './db/database.db'
try:
print "INITILIZATION..."
con = sqlite3.connect(dbname)
cursor = con.cursor()
cursor.execute("SELECT name FROM sqlite_master WHERE type='table';")
tables = cursor.fetchall()
for tbl in tables:
print "\n######## "+tbl[0]+" ########"
cursor.execute("SELECT * FROM "+tbl[0]+";")
rows = cursor.fetchall()
for row in rows:
print row
print(cursor.fetchall())
except KeyboardInterrupt:
print "\nClean Exit By user"
finally:
print "\nFinally"
Upvotes: 2
Reputation: 1917
I've implemented a sqlite table schema parser in PHP, you may check here: https://github.com/c9s/LazyRecord/blob/master/src/LazyRecord/TableParser/SqliteTableDefinitionParser.php
You can use this definition parser to parse the definitions like the code below:
$parser = new SqliteTableDefinitionParser;
$parser->parseColumnDefinitions('x INTEGER PRIMARY KEY, y DOUBLE, z DATETIME default \'2011-11-10\', name VARCHAR(100)');
Upvotes: 0
Reputation: 223
After a lot of fiddling I found a better answer at sqlite docs for listing the metadata for the table, even attached databases.
meta = cursor.execute("PRAGMA table_info('Job')")
for r in meta:
print r
The key information is to prefix table_info, not my_table with the attachment handle name.
Upvotes: 7
Reputation: 401
Apparently the version of sqlite3 included in Python 2.6 has this ability: http://docs.python.org/dev/library/sqlite3.html
# Convert file existing_db.db to SQL dump file dump.sql
import sqlite3, os
con = sqlite3.connect('existing_db.db')
with open('dump.sql', 'w') as f:
for line in con.iterdump():
f.write('%s\n' % line)
Upvotes: 21
Reputation: 7516
You can fetch the list of tables and schemata by querying the SQLITE_MASTER table:
sqlite> .tab
job snmptarget t1 t2 t3
sqlite> select name from sqlite_master where type = 'table';
job
t1
t2
snmptarget
t3
sqlite> .schema job
CREATE TABLE job (
id INTEGER PRIMARY KEY,
data VARCHAR
);
sqlite> select sql from sqlite_master where type = 'table' and name = 'job';
CREATE TABLE job (
id INTEGER PRIMARY KEY,
data VARCHAR
)
Upvotes: 112
Reputation: 48619
I'm not familiar with the Python API but you can always use
SELECT * FROM sqlite_master;
Upvotes: 37