Reputation: 3
I need a method to clone say 4 div's with id's like d_1, d_2, d_3, d_4 including the contents inside each div all at once and then detach all divs, and then I need to find copy of d_1 and its contents from the clone and append it again to the page.
something like:
var cloned=$('[id^="d_"]').clone();
$('[id^="d_"]').detach();
and then find div with id =d_1
from clone and append it to body.
Is it possible?
Upvotes: 0
Views: 121
Reputation: 1456
Use Document Fragment.
var $documentFragment = $(document.createDocumentFragment());
$('[id^="d_"]').each(function(){
$documentFragment.append($(this).clone().addClass("_cloned"));
});
$documentFragment.clone().appendTo(document.body);
If you want looking for an element into the fragment, you can do this:
$(document.body).find("#d_1._cloned"). ... ;
If you want to remove all the element and then append only the first copied into fragment:
$("._cloned", document.body).remove();
$documentFragment.find("#d_1").clone().appendTo(document.body);
Upvotes: 1
Reputation: 858
You can appendTo()
an element to detach and move an element elsewhere.
var els = $('[id^="d_"]')
els.detach();
els.each(function() {
if (this.id.indexOf('d_1') !== -1) {
$(this).appendTo(document.body);
}
});
// do something else with els later, too.
Upvotes: 1