CODEWITHSUNDEEP
directxshader
pixelknight
pixelknight

Reputation: 273

Updating float4 declaration from dx9 to dx11

There's a shader which was given which I'm trying to update to be compatible with the newest Unity 5 (presumably dx11). I don't understand how float4 basic instantiation from dx9 was working. Can someone help me understand the following syntax and then provide an equivalent dx11 syntax?

I understand that float4 normally uses x,y,z,w or xyz,y as arguments, but what does did a single float argument do? Did float4(0.01) make {.01,0,0,0} or does float4(.01) make {.01,.01,.01,.01}?

Original code from the shader:

float4 Multiply19 = float4( 0.01 ) * float4( 0 );

Upvotes: 0

Views: 93

Answers (1)

Luis Yanes
Luis Yanes

Reputation: 347

It should make a new float4 with all members (xyzw) set to 0.01 and then multiply all that by 0, effectively making Multiply19 a (0, 0, 0, 0) float4.

Upvotes: 1

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