CODEWITHSUNDEEP
groovy
KitKarson
KitKarson

Reputation: 5637

Groovy - List Sum

I am trying to sum all the numbers in the range (0 to 9) which can be divided by 3 or 5.

Approach 1:

    def result = (0..9).findAll { 
        (it % 3 == 0 || it % 5 == 0)
    }.sum()
    println result

Prints 23 which is as expected.

Approach 2: Same as above. But am trying to ignore a temp variable result & print directly. 

    println (0..9).findAll {
        (it % 3 == 0 || it % 5 == 0)
    }.sum()

Prints [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

What is going on here? Why is showing the entire list instead of the sum in the Approach 2.

Approach 3: Same as approach 2. Printing it directly. But moved the range to a variable.

    def lst = 0..9
    println lst.findAll {
        (it % 3 == 0 || it % 5 == 0)
    }.sum()

Prints 23 again.

Does Groovy expect me to have a temp variable always :( ??

Upvotes: 1

Views: 1388

Answers (1)

tim_yates
tim_yates

Reputation: 171084

The groovy parser thinks you're doing

println (0..9)

And then doing the rest of it to the result of the println

Just give the parser a helping hand with an outer set of parentheses

println( (0..9).findAll {
    (it % 3 == 0 || it % 5 == 0)
}.sum() )

Upvotes: 5

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