CODEWITHSUNDEEP
python
Flo
Flo

Reputation: 11

How To Remove Quotes From String in Python

Currently I have a list of strings, lets say:

list1 = [1,2,3,4]

I want to convert this list of numbers into their corresponding letters, using:

output = [chr(ord((str(x+96)))) for x in list1]

When I do this, I get an error saying the program expects a string length of one, but in my code it gives a string length of 3 because of the '' around each number after it is converted into a string. The conversion into a string is necessary because it has to be in the string format in order for ord to work.

So my question to you guys is how can I fix this and/or get rid of these quotes?

In case anyone was wondering, it is supposed to come out as

output = [a,b,c,d]

Upvotes: 0

Views: 2331

Answers (5)

Chris Hanning
Chris Hanning

Reputation: 143

Assuming you only want a string to print:

>>> list1 = [1, 2, 3, 4]
>>> pretty_string = ""
>>> # strings are immutable so need to
>>> # create new and assign to old variable name.
>>> for i in list1:
>>>     pretty_string = pretty_string + str(i) + ", "
>>> pretty_string = pretty_string[:-2] # remove trailing comma and space
>>> print(pretty_string)
1, 2, 3, 4

The str(i) method converts i to type string

Or, to print what you asked verbatim:

>>> print("output = [" + pretty_string + "]")
output = [1, 2, 3, 4]

If however you want a list of character representations of your integer list elements then:

>>> list1 = [1, 2, 3, 4] # integer values
>>> character_reps = []
>>> for i in list1:
>>>     character_reps.append(str(i))
>>> for i in character_reps:
>>>     print(i) # no need to convert as members already string types
1
2
3
4

Upvotes: 0

b4hand
b4hand

Reputation: 9770

Printing a list prints the string representation of its elements which includes the single quotes around the string elements inside your list. Instead just format the string yourself:

>>> '[{}]'.format(','.join([chr((x+96)) for x in list1]))
'[a,b,c,d]'

Or in printed form:

>>> print '[{}]'.format(','.join([chr((x+96)) for x in list1]))
[a,b,c,d]

The format method allows you to format a string. In this case, the curly braces are used as a placeholder for the value to include in the final string. The square brackets are part of the format to provide the actual array-like output. The join method takes an array of objects and joins them together to form a single combined string. In this case, I've joined several objects using a literal comma. This produces a comma separated string output. The inner list comprehension is essentially the code that you had already provided.

Upvotes: 1

rassa45
rassa45

Reputation: 3560

Can't you just do it the sane way which is 

string = " abcdefghijklmnopqrstuvwxyz"
newlist = []
for num in nums:
    newlist.append(string[num])

Upvotes: 0

salmanwahed
salmanwahed

Reputation: 9657

Your Answer will be like:

 output = [chr((x+96)) for x in list1]

ord takes a character and return the integer ordinal of the character. In your code, you are doing: 

ord((str(x+96)))

This is like, 

ord((str(1+96)))
ord('97')

So you are getting the error. ord's argument will be a one character string. like:

>>> ord('a')
>>> 97

But to get your expected output you don't need to use ord.

Upvotes: 2

Dair
Dair

Reputation: 16240

You have an integer, add 96 to it, the result should just be:

output = [chr(x+96) for x in list1]

You can ditch ord and str and entirely.

list1 = [1,2,3,4]

output = [chr(x+96) for x in list1]

print output #Prints: ['a', 'b', 'c', 'd']

Upvotes: 2

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