Reputation: 8972
i have a variable v
containing a data.frame
column name.
I now want to plot it against its index.
Normally, plotting a column against its index is easy:
df <- data.frame(a = c(.4, .5, .2))
ggplot(df, aes(seq_along(a), a)) + geom_point()
But in my case, I can’t figure out what incantations to do:
plot_vs <- function(df, count = 2) {
vs <- paste0('V', seq_len(count)) # 'V1', 'V2', ...
for (v in vs) {
# this won’t work because “v” is a string
print(ggplot(df, aes(seq_along(v), v)) + geom_point())
# maybe this? but it also doesn’t work (“object ‘v.s’ not found”)
v.s <- as.symbol(v)
print(ggplot(df, aes(seq_along(v.s), v.s)) + geom_point())
# this doesn’t work because i use seq_along, and seq_along('V1') is 1:
print(ggplot(df, aes_string(seq_along(v), v)) + geom_point())
}
}
plot_vs(data.frame(V1 = 4:6, V2 = 7:9, V3 = 10:12))
Upvotes: 0
Views: 1048
Reputation: 8972
@shadow’s comment gave the hint to find the solution, namely aes_q
:
plot_vs <- function(df, count = 2) {
vs <- paste0('V', seq_len(count)) # 'V1', 'V2', ...
for (v in vs) {
v = as.name(v)
print(ggplot(df, aes_q(substitute(seq_along(v)), v)) + geom_point())
}
}
plot_vs(data.frame(V1 = 4:6, V2 = 7:9, V3 = 10:12))
Upvotes: 0
Reputation: 22353
Your question title explicitly states that you want to do this without aes_string
. Here's how you do it with aes_string
: use paste
.
plot_vs <- function(df, count = 2) {
vs <- paste0('V', seq_len(count)) # 'V1', 'V2', ...
for (v in vs) {
print(ggplot(df, aes_string(paste("seq_along(", v, ")"), v)) + geom_point())
}
}
plot_vs(data.frame(V1 = 4:6, V2 =7:9, V3 = 10:12))
Upvotes: 1
Reputation: 6124
library(ggplot2)
df <- data.frame(a = c(.4, .5, .2))
v <- "a"
df$num<-seq(nrow(df))
ggplot(df, aes_string("num", v)) + geom_point()
Upvotes: 0