Reputation: 3798
I have searched but still didn't get easy and proper answer, Below is my code.
#include <iostream>
using namespace std;
class Parent
{
private:
int a;
public:
Parent():a(3) { cout << a; }
};
int main()
{
Parent obj;
return 0;
}
Can you add additional lines of code that can prove or show me that initializer list call before constructor?
Upvotes: 0
Views: 55
Reputation: 351
You don't get variable "a" value 10 in this program , a assigned before constructor method called .
#include<iostream>
using namespace std;
class Test
{
public:
int a,b;
public:
Test():a(b){
b=10;
}
};
int main()
{
Test obj;
cout<<"a :"<<obj.a<<" b:"<<obj.b;
return 0;
}
Upvotes: 1
Reputation: 10596
I would modify you code ever so slightly:
#include <iostream>
using namespace std;
class Parent
{
public:
int a;
public:
Parent():a(3){
a = 4;
}
};
int main()
{
Parent obj;
cout << obj.a;
return 0;
}
The output is 4
, thus a
was initialized with 3
and then assigned 4
.
Upvotes: 3
Reputation: 62878
Simply add data member, which has constructor, which prints something. Example:
#include <iostream>
using namespace std;
struct Data {
Data(int a) {
cout << "Data constructor with a=" << a << endl;
}
};
class Parent
{
private:
Data a;
public:
Parent():a(3){
cout << "Parent constructor" << endl;
}
};
int main()
{
Parent obj;
return 0;
}
Output:
Data constructor with a=3
Parent constructor
Conclusion: Data
constructor was called before constructor body of Parent
.
Upvotes: 1
Reputation: 1983
This is best shown with multiple classes:
#include <iostream>
class A
{
public:
A()
{
std::cout << "Hello World!" << std::endl;
}
};
class B
{
private:
A* a;
public:
// Call a's constructor
B():a(new A)
{
// Some code
}
~B()
{
delete a;
}
};
int main()
{
B obj;
return 0;
}
Upvotes: 0