CODEWITHSUNDEEP
java
Cnorwood7641
Cnorwood7641

Reputation: 336

Convert int array into a bunch of ints

I have 

public int average(int grades[]){return **}

and I call it with: average({80, 90, 100})

I want to separate the array into three individual ints.

Upvotes: 1

Views: 76

Answers (3)

Shar1er80
Shar1er80

Reputation: 9041

The fact that the data is in an array, you already have "n" individual ints. Each element of the array is an individual int that you can access via an index value ranging from 0 to (n - 1), where n is the length of the array.

So an array of 3 ints would have indices 0, 1, 2.

With that, if your average() is to compute the average of the ints you have in your array, just loop through your array and accumulate the values into a sum and divide that sum by the number of ints that you have.

public static void main(String[] args) throws Exception {
    System.out.println("Average: " + average(new int[] {80, 90, 100}));
}

public static int average(int[] grades) {
    int sum = 0;
    for (int i = 0; i < grades.length; i++) {
        sum += grades[i];
    }
    return sum / grades.length;
}

Results:

Average: 90

Upvotes: 0

swingMan
swingMan

Reputation: 752

If you're looking to compute the average of several integers in your grades array, as is implied by the name of your method, and regardless of how many items are in the array, you can use Java 8 streams. Just a suggestion.

public int average(int[] grades)
{
    OptionalDouble od =  Arrays.stream(grades).average();
    if(od.isPresent())
    {
        return (int)od.getAsDouble();
    }
    return 0; //error condition to be checked by calling method.
}

Upvotes: 0

SCS
SCS

Reputation: 121

public int average1 = average[0];
public int average2 = average[1];
public int average3 = average[2];

Hope i helped :) Edit: Whoops forgot to put a semicolon xD

Upvotes: 3

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