CODEWITHSUNDEEP
pythonif-statementconditional-statements
Jeflopo
Jeflopo

Reputation: 2262

One liner conditional, multiple variables and check that all of them are not false?

How I can make a conditional in python that checks for this three keywords defined in the dictionary and that they are not False ?

settings = {
    'proxy_host': '127.0.0.1',
    'proxy_port': 8080,
    'proxy_protocol': 'socks',
}

I have tried with the sentence you can see below. But this is only checking that these keywords exists in the dictionary settings without bothering about what type of value has.

if 'proxy_host' and 'proxy_port' and 'proxy_protocol' in settings:

I only want my IF to True If none of the keywords are falsely and they all exist as keys.

Upvotes: 2

Views: 86

Answers (3)

konart
konart

Reputation: 1834

if ('proxy_host' in settings and isinstance(settings['proxy_host'], str)) 
   and ('proxy_port' in settings and isinstance(settings['proxy_port'], int)) 
   and ('proxy_protocol' in settings and isinstance(settings['proxy_protocol']), str)):

Upvotes: 2

James Mills
James Mills

Reputation: 19030

Use a simple generator expression and all():

if all(d.get(k) for k in keys):

Example:

keys = ['proxy_host', 'proxy_port', 'proxy_protocol']
if all(settings.get(k) for k in keys):
    print("Settings good!")
else:
    print("Missing setting!")

Upvotes: 1

khelwood
khelwood

Reputation: 59114

If you want to check that all of the keys are in the dict and map to a non-falsey value, you can check this:

if all(settings.get(x) for x in ['proxy_host','proxy_port', 'proxy_protocol']):

dict.get(key) will return None if the key is not in the dict, so you you can check "is in the dict and value is not falsey" in one go.

Upvotes: 1

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