CODEWITHSUNDEEP
python
DevEx
DevEx

Reputation: 4561

How to skip over current element in a python list

How I can loop over a python list, add each item to another list except the current item:

list = [1,2,8,20,11]

for i,j in enumerate(list):
    print j[i+1:]
#this will only give [2,8,20,11] then [8,20,11],[20,11], [11]

#but I want something like [2,8,20,11], [1,8,20,11],[1,2,20,11]... etc.
#then 1,8,20,11
#then

Upvotes: 1

Views: 76

Answers (2)

Jon Clements
Jon Clements

Reputation: 142136

Looks like you're after combinations, eg:

>>> from itertools import combinations
>>> data = [1,2,8,20,11]
>>> list(combinations(data, 4))
[(1, 2, 8, 20), (1, 2, 8, 11), (1, 2, 20, 11), (1, 8, 20, 11), (2, 8, 20, 11)]

Upvotes: 3

ZdaR
ZdaR

Reputation: 22954

you may use list slicing as:

lst = [1,2,8,20,11]
for i in xrange(len(lst)):
    print lst[:i]+lst[i+1:]

>>> [2, 8, 20, 11]
    [1, 8, 20, 11]
    [1, 2, 20, 11]
    [1, 2, 8, 11]
    [1, 2, 8, 20]

Upvotes: 2

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