CODEWITHSUNDEEP
c
Dan
Dan

Reputation: 448

Getting the last digit of number counting up

Say I have a number which is counting from 0 to 10000,
0,1,2,3 ... 9998, 9999, 10000

How am I able to only display the last digit on this number. eg: 0,1,2,3,4,5,6,7,8,9,0,1,2...

I have this code but i'm not sure how to implement what I want.

if (count_a > 9) {
//something here
count_a = 0; //resets it back to 0
} else { //count_a is less than 9
count_a =((newtime-original_time)/100); //to get ms //this counts up in the way which I have stated above.

How can I loop the ((newtime-original_time)/100) to go back to 0 once it is >9?

Upvotes: 2

Views: 206

Answers (3)

Shravya Boggarapu
Shravya Boggarapu

Reputation: 592

To get the last digit. do count_a = num % 10

To loop back the ((newtime-original_time)/100) expression when count_a > 9 (can be re-written as when count_a == 0 since after 9, you get 0 in this case so you code should be :

for(num = 0; num <MAX; num++)
{
    count_a = num % 10;
    if (count_a == 0)
    {
        original_time = newtime; // this will make the expression = 0
    }
    count_a = ((newtime-original_time)/100);
}

Hope this helps :)

Upvotes: 0

Gopi
Gopi

Reputation: 19864

I hope this is what you want 

num % 10

for digit num the result of the above operation will always range from 0 to 9.

Upvotes: 2

Greg Hewgill
Greg Hewgill

Reputation: 992955

To extract the last (decimal) digit from a number x, use:

x % 10

The % represents the modulo operator, which equals the remainder after dividing by 10.

Upvotes: 4

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