Reputation: 168
If I have a file that contains for example:
results1: 2, 4, 5, 6, 7, 8, 9
results2: 5, 3, 7, 2, 8, 5, 2
I want to add the integers from each line to a array. One array for each line. How can I do this with code that does only read the integers?
Here's what I got this far
String data = null;
try {
Scanner in = new Scanner(new File(myFile));
while (in.hasNextLine()) {
data = in.nextLine();
numbers.add(data);
}
in.close();
} catch (Exception e) {
}
Upvotes: 0
Views: 1373
Reputation: 308753
Easy.
One line per array, not two as you have it. New line after each one.
Read each line as a String, discard the leading "resultsX:", and split what remains at a delimiter of your choosing (e.g. comma). Parse each into an integer and add it to a List.
I don't think that leading "results1: " is adding any value. Why do you have that?
Upvotes: 3
Reputation: 7462
Open the file with a BufferedReader br
and then read it line by line.
Store each line in an int array and add all those int arrays to a list. At the end, this list will contain all the int arrays that we wanted, so iterate this list to do whatever you want to do next.
String filePath = "/path/to/file";
BufferedReader br = null;
List<Integer[]> arrays = new ArrayList<>(); //this contains all the arrays that you want
try {
br = new BufferedReader(new FileReader(filePath));
String line = null;
while ((line = br.readLine()) != null) {
line = line.substring(line.indexOf(":")+2); //this starts the line from the first number
String[] stringArray = line.split(", ");
Integer[] array = new Integer[stringArray.length];
for (int i = 0; i < stringArray.length; ++i) {
array[i] = Integer.parseInt(stringArray[i]);
}
arrays.add(array);
}
} catch (FileNotFoundException ex) {
System.err.println(ex);
} catch (IOException ex) {
System.err.println(ex);
} finally {
try {
br.close();
} catch (Exception ex) {
System.err.println(ex);
}
}
Since ArrayLists keep insertion order, then, e.g., arrays.get(3)
will give you the array of the fourth line (if there is such a line) and arrays.size()
will give you the number of lines (i.e., int arrays) that are stored.
Upvotes: 0
Reputation: 581
Assuming you have an input file, like this:
2,4,5,6,7,8,9
5,3,7,2,8,5,2
here is a code snippet to load it:
String firstLine = "";
String secondLine = "";
File file = new File("path/to/file");
try {
BufferedReader br = new BufferedReader(new FileReader(file));
firstLine = br.readLine();
secondLine = br.readLine();
} catch(Exception e){
e.printStackTrace();
}
String[] firstResult = firstLine.split(",");
String[] secondResult = secondLine.split(",");
int[] firstIntegers = new int[firstResult.length];
for(int i = 0; i <= firstResult.length ; i++){
firstIntegers[i] = Integer.parseInt(firstResult[i]);
}
int[] secondIntegers = new int[secondResult.length];
for(int i = 0; i <= secondResult.length ; i++){
firstIntegers[i] = Integer.parseInt(secondResult[i]);
}
Upvotes: 0
Reputation: 1647
public static void main(String[] args) throws IOException {
BufferedReader reader=null;
try {
reader = new BufferedReader(new FileReader(new File("PATH TO FILE")));
// Only works if File allways contains at least two lines ... all lines after the second
// will be ignored
System.out.println(String.format("Array 1 : %s", Arrays.toString(stringArray2IntArray(readNextLine(reader)))));
System.out.println(String.format("Array 2 : %s", Arrays.toString(stringArray2IntArray(readNextLine(reader)))));
} finally {
if (reader!=null) {
reader.close();
}
}
}
private static Integer[] stringArray2IntArray(String[] numStrings) {
List<Integer> result = new ArrayList<Integer>();
for (int i = 0; i < numStrings.length; i++) {
result.add(Integer.parseInt(numStrings[i].trim()));
}
return result.toArray(new Integer[numStrings.length]);
}
private static String[] readNextLine(BufferedReader reader) throws IOException {
return reader.readLine().split(":")[1].split(",");
}
Upvotes: 0