Reputation: 57
Here is my code example
<form action="next2.php" method="post" name="next2" id="next2" onsubmit="return submitForm();">
Below is my function
<script type="text/javascript">
function submitForm()
{
var name = document.getElementById("name").value;
return false;
}
</script>
On press, the form still submit, but if i change
onsubmit="return false;"
then the form won't submit, how do I use the function to return false as i need do some if else validation
Upvotes: 2
Views: 77
Reputation: 8513
I like to make an invisible button for the actual submit which is only triggered after form validation:
function validate() {
var valid = true;
$.each($('input'), function(){
valid = valid && $(this).val().length > 0;
})
if (valid) {
$('#realSubmit').click();
} else {
alert('Please fill out all fields!');
}
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="next2.php" method="post" name="next2" id="next2" onsubmit="return submit();">
<input type="text" placeholder="Enter Name" />
<input type="password" placeholder="Enter Password" />
<button type="button" onclick="validate()">Submit</button>
<button type="submit" id="realSubmit" style="display:none"></button>
</form>
Upvotes: 0
Reputation: 42099
<script type="text/javascript">
function submitForm() {
return false;
}
</script>
<form
action="next2.php"
method="post"
name="next2"
id="next2"
onsubmit="return submitForm();"
>
submit
is already a function for the form, you should call your JavaScript function something different, for instance submitForm
as in the above.
Upvotes: 2
Reputation: 800
just remove the semicolon in your function and place a alert in your function to make sure whether the function is called first.and then try to add validation
Upvotes: 0