CODEWITHSUNDEEP
pythonfor-loop
splint
splint

Reputation: 13

Creating a board in Python

I'm trying to create a board/grid on python 3.5 that looks like this:

enter image description here
The height/width are user inputs. This is what I currently have:

board = [['*' for i, row in enumerate(range(2))] for row in enumerate(range(3))]
for i, row in enumerate(board):
    actual_board = ' '.join(row)
    row_text = '{0} '.format(i)
    print (row_text + actual_board)

This outputs:

0 * *
1 * *
2 * *

Upvotes: 0

Views: 3872

Answers (2)

Paul Rooney
Paul Rooney

Reputation: 21609

Another approach, slightly more verbose code.

def makeboard(rows, cols):
    board = []
    for r in range(rows):
        brow = []
        for c in range(cols):
            if r == c == 0:
                 brow.append(' ')
            elif r == 0:
                 brow.append(str(c-1))
            elif c == 0:
                 brow.append(str(r-1))
            else:
                 brow.append('*')
        board.append(brow)
    return board

b = makeboard(4,3)

for row in b:
    print ' '.join(row)

Upvotes: 0

TigerhawkT3
TigerhawkT3

Reputation: 49318

When you create the board, you're not using i or row - there's no need to enumerate() a range(). Just use range().

board = [['*' for column in range(2)] for row in range(3)]
print(' ' + ''.join(map(str, range(2)))) # print column labels
for row, item in enumerate(board): # for each row
    print(str(row) + ''.join(item)) # print the row label and contents

Result:

 01
0**
1**
2**

Upvotes: 1

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