CODEWITHSUNDEEP
javaregex
MrPencil
MrPencil

Reputation: 964

Get the right number in the String

I am trying to pick the integer value 30in this string which hast the form \s\d\d\s. I have tried the code below but I am getting the Minute value 30 at the end of the line too but I want just to get the value 30 which has this form \s\d\d\s. How can I fix that?

I appreciate any help.

Line before doing m.group(); in this line are two 30 number

wall street 4 06:28 07:29 07:59 08:29 08:59 30 19:59 20:29 21:04 22:04 23:04 00:04 00:30

Line after:

wall street 4 06:28 07:29 07:59 08:29 08:59 19:59 20:29 21:04 22:04 23:04 00:04 00:

Result should Looks like

wall street 4 06:28 07:29 07:59 08:29 08:59 19:59 20:29 21:04 22:04 23:04 00:04 00:30

my Code:

    Pattern pattern = Pattern.compile("(?<=\\d\\s)\\d{2}(?=\\s\\d)");

    Matcher m = pattern.matcher(line);
    while (m.find()) {
        value = Integer.parseInt(m.group().trim());

        line = line.replace(m.group(), " ").replaceAll(" +", " ");


    }

Upvotes: 2

Views: 87

Answers (3)

MT0
MT0

Reputation: 167822

Instead of using a independently calling line.replace(m.group(), " ").replaceAll(" +", " "); you can use the matcher's replace functions.

Like this:

IDEONE

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class Test {
    public static void main (String[] args) throws java.lang.Exception
    {
        String line = "wall street 4 06:28 07:29 07:59 08:29 08:59 30 19:59 20:29 21:04 22:04 23:04 00:04 00:30";
        System.out.println( "Input:  " + line );
        Pattern pattern = Pattern.compile("(?<=\\d{2}:\\d{2})\\s+\\d{2}(?=\\s)");
        Matcher m = pattern.matcher(line);
        while (m.find()) {
            int value = Integer.parseInt(m.group().trim());
            line = m.replaceFirst("");
            System.out.println( "Output: " + line );
        }    
    }
}

Upvotes: 0

karthik manchala
karthik manchala

Reputation: 13640

Why is it happening?

Your pattern is OK and matching 30 as required.. but in the while loop.. you are replacing m.group() (which is now 30) with " ".. hence all the instances where you have 30 will be replaced..

How to fix?

You can replace the pattern directly.. i.e:

line = line.replaceAll("(?<=\\d\\s)\\d{2}(?=\\s\\d)", "").replaceAll(" +", " ");

Code:

Pattern pattern = Pattern.compile("(?<=\\d\\s)\\d{2}(?=\\s\\d)");
Matcher m = pattern.matcher(line);
while (m.find()) {
    value = Integer.parseInt(m.group().trim());
}
line = line.replaceAll("(?<=\\d\\s)\\d{2}(?=\\s\\d)", "").replaceAll(" +", " ");
System.out.println(line);

See Ideone Demo

Upvotes: 1

anubhava
anubhava

Reputation: 784928

You can just do:

line = line.replaceAll("(?<=\\d\\s)\\d{2}\\s*(?=\\d)", "");

to get your output.

RegEx Demo

Upvotes: 3

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