CODEWITHSUNDEEP
javascriptphpjqueryhtmlfunction
Zara Rebecka Elisabeth Zentio
Zara Rebecka Elisabeth Zentio

Reputation: 209

Javascript function onclick

I am trying to call a jquery script that will post data to a PHP form. Been googling this for 5h now but i cant seems to solve it on my own. The Script looks like this.

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script language="JavaScript" type="text/javascript">
    function postscrape(igid, iguser, groupid) {

        alert(igid);
        $.post("scrapeadder.php", {
                instagramid: igid,
                username: iguser,
                groupid: groupid
            },
            function(data, status) {
                alert("Data: " + data + "\nStatus: " + status);
            });
    };
</script>

And my HTML/PHP code to call this function looks like:

  echo '<td><button type="button" class="btn btn-success datascraper" name="addscrape" id="addscrape" onclick="postscrape('.$row["instagram_id"].', '.$row["user_name"].', 1);">Add to Scrape</button></td>';

The error i get is: Uncaught ReferenceError: X is not defined

Where X = The iguser (which gets from $row["user_name"] If i check the HTML code on the homepage it list all the $rows correct. So my guess is i messed up in the function.

Upvotes: 1

Views: 49

Answers (2)

Christoph Sommer
Christoph Sommer

Reputation: 6943

You didn't quote the user name. The 

echo 'postscrape('.$row["user_name"].')'

yields 

postscrape(X)

...where X is undefined.

Upvotes: 2

Barmar
Barmar

Reputation: 781004

You need to put the user name in quotes.

onclick="postscrape('.$row["instagram_id"].', \''.$row["user_name"].'\', 1);"

Upvotes: 2

Related Questions