CODEWITHSUNDEEP
phpjsondecimalformat
Lutianna
Lutianna

Reputation: 543

PHP: how to prevent json_encode rounding number automatically?

Having a big problem with json_encode it automatically round off the digits but I need 2 decimal points on every digits.

PHP:

<?php
$numbers = [1.00,2.00];

foreach ($numbers as $i => $number) 
{
      $numbers[$i] = number_format($number, 2, '.', null);
}

echo json_encode($numbers,  JSON_NUMERIC_CHECK);
?>

OUTPUT: [1,2]

EXPECTED OUTPUT: [1.00,2.00]

how can I prevent every digits for not rounding off automatically?

PS: NOT A STRING :)

Upvotes: 3

Views: 6269

Answers (3)

deceze
deceze

Reputation: 522382

$numbers = [1.00,2.00];

Here your numbers have already lost their "decimal values". Seriously, try var_dump on them right after this line, you won't get .00 from that either.

Floating point numbers and integers only contain the numeric value, formatting is not preserved in any way. It's not a json_encode problem, it's a fundamental truth of numeric values in computing.

If you want to preserve formatting you need to use strings all the way through.

Upvotes: 2

Anthony
Anthony

Reputation: 37065

Sounds like you are looking for JSON_PRESERVE_ZERO_FRACTION, available in PHP 5.6.6. Prior versions, you'll need to either convert to string or suck it up and accept that floats and integers are equivalent when there's no fractional value.

$numbers = [1.00,2.00];

echo $res = json_encode($numbers,JSON_PRESERVE_ZERO_FRACTION);

Upvotes: 6

Deep Kakkar
Deep Kakkar

Reputation: 6305

You can use your code in this way as follows:

<?php
 $numbers = [1.00,2.00];

 foreach ($numbers as $i => $number) 
 {
    $numbers[$i] = number_format($number, 2, '.', null);
 }

  echo $res = json_encode($numbers); // ["1.00","2.00"]
  echo str_replace('"', '', $res); //[1.00,2.00]
 ?>

and Your EXPECTED OUTPUT: [1.00,2.00] which is same.

Upvotes: -1

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