Reputation: 2734
I have a list, containing the alphabet.
When outputting with foreach, i will currently receive this result:
What i would like to achieve is this
Ive tried the following, but really, i doesent find it a good or stable solution - and the letters/indexes are presented twice.
@{
var ie = 0;
int sortI = 0;
}
int columns = 3;
int dictLength = ToShow.Count();
int rows = dictLength/columns;
int sortS = 1;
List<int> hasKey = new List<int>();
var newDict = new Dictionary<string, List<LoopItem> >();
if( sort.Equals("alphabetically") )
{
while( sortI <= rows )
{
<text>Column @( ToShow.Keys.ElementAt(sortI) ) - </text>
while( sortS <= ( columns ) )
{
int index = (( sortS * columns ) + sortI); //(( sortS * columns ) + ( 1 + sortI ));
if( hasKey.Contains(index) ) { continue; } else
{
<text>Column @( ToShow.Keys.ElementAt(index) ) - </text>
sortS++;
hasKey.Add(index);
}
}
<text><br /></text>
sortS = 1;
sortI++;
}
sortS = 1;
sortI = 1;
<text><hr /></text>
foreach( var item in ToShow )
{
<text><br/>::Række 1::<br /></text>
while( columns >= sortS )
{
<text>Indsæt @(sortI+sortS)<br /></text>
sortS++;
}
sortI++;
sortS = 1;
}
}
}
Are there any algorithm for this kind of stuff? Or a simple function?
Thanks in advance
Upvotes: 0
Views: 1194
Reputation: 186
It really applies to being able to "vertically" group and sort any (IComparable) collection, a series of characters such as the alphabet probably being the most visible/common one.
Depending on the requirement, either number of rows (Bob's answer) or number of items per column:
public static IList<IList<T>> groupCollection<T>(List<T> comparable, int groupSize, bool sortAscending = true) where T : IComparable
{
var groups = new List<IList<T>>();
if (comparable != null && groupSize > 0)
{
var items = sortAscending ? comparable.OrderBy(item => item).ToList() : comparable.OrderByDescending(item => item).ToList();
int totalItems = comparable.Count;
int totalGroups = totalItems % groupSize > 0 ? totalItems / groupSize + 1 : totalItems / groupSize;
for (int groupIndex = 0; groupIndex < totalGroups; groupIndex++)
{
int k = 0;
for (int j = groupIndex; j < totalItems && k < groupSize; j += totalGroups)
{
k++;
if (groups.ElementAtOrDefault(groupIndex) == null)
{
groups.Add(new List<T>());
}
groups[groupIndex].Add(items[j]);
}
}
}
return groups;
}
Upvotes: 0
Reputation: 3323
Quick Example with LINQ:
void Main()
{
var targetNrOfRows = 3;
var alphabet = new[] { 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z' };
var r = alphabet
.Select((el, i) => new { row = i / targetNrOfRows, col = i % targetNrOfRows, el2 = el })//compute indices of matrix 'A B C' and so forth
.Select(el => new { row2 = el.col, col2 = el.row, el3 = el.el2 })//Transpose said Matrix and thus obtain the desired matrix
.OrderBy(el => el.row2).ThenBy(el => el.col2);//Order by row and then by column
for (int i = 0; i < targetNrOfRows; i++)//print it out
{
var row = r.Where(el => el.row2 == i).Select(el => el.el3);//get i-th row
foreach (var item in row)
{
Console.Write(item);
}
Console.WriteLine();
}
r.Dump();
}
Let me know whether you have any questions.
Upvotes: 0
Reputation: 236
If you know how many letters you want to present on each row you could do something like this:
var alphabet = new []{'A', 'B', 'C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};
var rows = 3;
var alphabetIndex = 0;
for(var row = 0; row < rows; row++) {
for(var letter = alphabetIndex; letter < 26; letter += rows) {
Console.Out.Write(alphabet[letter] + " ");
if(letter + rows >= 26)
alphabetIndex = (letter + rows) - 26;
}
Console.Out.WriteLine();
}
Rows will set how many rows you want, other than that it should work out for you.
Upvotes: 2