CODEWITHSUNDEEP
phpjqueryhtml
Yu Yenkan
Yu Yenkan

Reputation: 765

jquery.load("something.php") not working well

i have a something.php which will print the option of dropdownlist,\

then i load the .php file with

$("#dropdownlist").load("something.php");

after i load, the output is displayed, but when i change the selected value, in debug mode i din not saw a selected="selected" on the option of dropdownlist and i cannot set a selectedvalue to the dropdownlist also with

$("#dropdownlist").val("2");

any one know why this happen and how can i solve it?

add-on code

--print option on .php--

while (isset($StatusArr[$loopCount])) {
if ($loopCount == 0) {
    $selected = "selected='true'";
} else {
    $selected = "";
}

echo "<option value='"
. $StatusArr[$loopCount][0]
. "' "
. $selected
. " >"
. $StatusArr[$loopCount][1]
. "</option>";

$loopCount ++;
}

---call in .js----

$('#select').load("../something.php", function (respond, fstatus, xhr) {
    if (fstatus === "success") {
        if (status !== "missing") {
            $('#status').prop("selectedIndex", 3);                
        }
    } else {
        alert("Load data " + fstatus + "\n" + xhr.status + " " + xhr.statusText);
    }
});

Upvotes: 0

Views: 49

Answers (1)

chris97ong
chris97ong

Reputation: 7060

$("#dropdownlist").prop("selectedIndex", 1);

This jQuery code sets the selected option of the dropdownlist to the 2nd option.

Upvotes: 4

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