CODEWITHSUNDEEP
phpunit-testingsymfonyphpunit
thitami
thitami

Reputation: 838

Calling a method of a mock object

I am testing a service with PHPUnit.

I am using setUp() to create mock objects of the dependencies that my service accepts, like this:

 public function setUp()
    {
        $this->fooManagerMock = $this->getFooManagerMock();
        $this->barManagerMock = $this->getBarManagerMock();
        $this->treeManagerMock = $this->getTreeManagerMock();
        $this->loggerMock = $this->getLoggerMock();

     $this->myService = new MyService($this->fooManagerMock, $this->barManagerMock, $this->treeManagerMock, $this->loggerMock);
    }

Bundle\Tests\Service\MyTest::testServiceWithValidData

   /**
     * @dataProvider getServiceValidCaseData
     */
    public function testServiceWithValidData($case)
    {
         $this->assertTrue($this->myService->serve($fooArray));
    }

It turns out that a entity manager that in my serve() function, I am having something like this:

return $this->fooManager->find($fooId) !== null;

in this case $this->fooManager is instance of Mock_FooManager_4038382a and the whole test fails.

Any suggestions are more than welcome.

UPDATE

/**
     * @return \PHPUnit_Framework_MockObject_MockBuilder
     */
    private function getFooManagerMock()
    {
        return $this->getMockBuilder(
            '\MyBundle\Entity\Manager\FooManager'
        )->disableOriginalConstructor()->getMock();
    }

Example for @matteo

I was expecting $fooManager->find($id) to return me a specific instance of Foo, such as:

\MyBundle\Manager\FooManager{
"id" : 234234,
"status" : "pending".
"color" : "yellow",
"tree" : [
         "id" : 2345,
         "height" :160
       ]
}

Upvotes: 1

Views: 50

Answers (1)

Matteo
Matteo

Reputation: 39380

You must specify in the test case which behaviour the mocked entity must do, try adding this code in the testServiceWithValidData method, before call the tested service:

       $fooMockObj = $this->getMock('\MyBundle\Entity\Foo');
       // Eventually mock some method
       // PS You can return a concrete instance too
       // $fooMockObj= new  \MyBundle\Entity\Foo();

        $this->fooManager
            ->expects($this->any())
            ->method('find')
//            ->with($anOptionalInputId)
             ->will($this->returnValue($fooMockObj));

Hope this help

Upvotes: 2

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